Neo4j Cypher：根据另一个查询过滤查询结果

Question

我正在尝试查找一个查询唯一的名称列表，并排除两个查询结果之间共有的名称。例如，我想要学生 A、B 和 C 参加的类的名称。并从该列表中排除学生 D 和 E 参加的类。在帮助下这个问题的答案 ()，我尝试了这个 Cypher 代码并且它有效，但我得到的结果是节点。我希望它作为名称列表，而不是节点。

Match (m:class)-[r]-(n:student) where n.name in ['aa','bb','cc']    
WITH COLLECT(m) AS EXCLUDED
MATCH  (m1:class)-[r1]-(n1:student) where n1.name in ['dd','ee'] 
WITH EXCLUDED, COLLECT(m1) AS included
RETURN FILTER(m1 IN included WHERE NOT m1 IN EXCLUDED)

谢谢！

Answer 1

你可以有另一个 WITH 和 UNWIND。

Match (m:class)-[r]-(n:student) where n.name in ['aa','bb','cc']    
WITH COLLECT(m) AS EXCLUDED
MATCH  (m1:class)-[r1]-(n1:student) where n1.name in ['dd','ee'] 
WITH EXCLUDED, COLLECT(m1) AS included
WITH FILTER(m1 IN included WHERE NOT m1 IN EXCLUDED) as _results
UNWIND _results as results
RETURN results.name

注意： FILTER() 在 neo4j 3.5 中被弃用，在 4.0 中被移除以支持 List Comprehension

Neo4j Cypher：根据另一个查询过滤查询结果

Neo4j Cypher: Filtering a query results based on another query

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