JS 如何从内部拒绝包装器承诺？

Question

如何从一个或内部拒绝包装承诺？换句话说，如何让数字“3”从不打印？当前输出：

1
2
3

预期输出：

1
2

new Promise(function(resolve, reject) {
  console.log(1)
  resolve()
})
.then(() => console.log(2))
.then(() => { // how to reject this one if internal fails?
  new Promise(function(resolve, reject) {
    reject(new Error('Polling failure'));
  })
  .then(() => console.log(21))
})
.then(() => console.log(3))

Answer 1

看来你只是少了一个 return

new Promise(function(resolve, reject) {
    console.log(1)
    resolve()
  })
  .then(() => console.log(2))
  .then(() => { // how to reject this one if internal fails?
    return new Promise(function(resolve, reject) {
        reject(new Error('Polling failure'));
      })
      .then(() => console.log(21))
  })
  .then(() => console.log(3))

Answer 2

为了拒绝来自 .then() 处理程序的承诺链，您需要：

使用`throw`

抛出任何值都会将承诺标记为不成功：

const p = new Promise(function(resolve, reject) {
  console.log(1)
  resolve()
})
.then(() => console.log(2))
.then(() => { throw new Error(); })
.then(() => console.log(3));


p
  .then(() => console.log("sucessful finish"))
  .catch(() => console.log("error finish"));

Return 一个被拒绝的承诺

最简单的方法是 Promise.reject:

const p = new Promise(function(resolve, reject) {
  console.log(1)
  resolve()
})
.then(() => console.log(2))
.then(() => Promise.reject("problem"))
.then(() => console.log(3));


p
  .then(() => console.log("sucessful finish"))
  .catch(() => console.log("error finish"));

JS 如何从内部拒绝包装器承诺？

JS how to reject wrapper promise from inside one?

javascript

es6-promise

使用`throw`

Return 一个被拒绝的承诺

JS 如何从内部拒绝包装器承诺？

JS how to reject wrapper promise from inside one?

javascript

es6-promise

使用throw

Return 一个被拒绝的承诺

使用`throw`