使用 python GUI 的 Tkinter 命令时出现 Tcl 错误

Question

我正在开发一个 GUI，用于对用户输入的文件夹中的视频进行缩减采样。这是基本框架： 1.On 按钮点击用户输入 path/directory 的视频 2.I 有一个下采样函数，它接受用户的这个输入（路径）并对视频进行下采样。编辑：我在相同的错误下看到了类似的答案，我已经尝试了解决方案但它不起作用并且给出了不同的错误。所以，相反，我发布这个是为了避免混淆，并想了解如何修复这个特定的问题。这是我的：


from tkinter import * 
from tkinter.ttk import *

from tkinter.filedialog import askopenfile 

root = Tk() 
root.geometry('200x100') 

def open_file(): 
    file = askdirectory() 
    if file is not None:
        return file#add if directory is not correct option
btn = Button(root, text ='Open', command = lambda:open_file())
btn.pack(side = TOP, pady = 10) 
#mainloop() 
def downsamplevideos(open_file):
    for video in os.listdir(open_file):
        input_file_name=video
        (
            ffmpeg
            .input('/Users/lala/Desktop/checktwo/{}'.format(input_file_name))
            .filter_('scale', 640, 360)
            .output("/Users/lala/Desktop/videos/downsampleda{}".format(input_file_name))
            .run(capture_stdout=True, capture_stderr=True)
        )
btn2 = Button(root, text="Select",command=lambda:downsamplevideos(open_file()))
btn2.pack(side = TOP, pady = 10)


This is opening a window with two button. But it is not working, that is it is not downsampling. Can anyone help me with this implementation?

Answer 1

当您在按下打开按钮后调用 open_file 时，文件路径不会存储在任何地方。这可以通过创建一个全局变量 directory 来解决，该变量将存储文件路径，以便可以在 downsamplevideos.

中使用

directory = None
def open_file(): 
    file = askdirectory() 
    if file is not None:
        global directory
        directory = file
btn = Button(root, text ='Open', command = lambda:open_file())
btn.pack(side = TOP, pady = 10) 
#mainloop() 
def downsamplevideos():
    global directory
    for video in os.listdir(directory):
        input_file_name=video
        (
            ffmpeg
            .input('/Users/lala/Desktop/checktwo/{}'.format(input_file_name))
            .filter_('scale', 640, 360)
            .output("/Users/lala/Desktop/videos/downsampleda{}".format(input_file_name))
            .run(capture_stdout=True, capture_stderr=True)
        )
btn2 = Button(root, text="Select",command=lambda:downsamplevideos())
btn2.pack(side = TOP, pady = 10)

使用 python GUI 的 Tkinter 命令时出现 Tcl 错误

Getting Tcl error while working with python Tkinter command for GUI

python

user-interface

tkinter

widget