如何在 Java 8 中的重复键映射中添加值

How to add values in duplicated key Map in Java 8

我想在 Java 中的重复键映射中添加值 8.

举个例子:

例如:如果 strArr 是 ["B:-1", "A:1", "B:3", "A:5"] 那么我的程序应该 return 字符串 A:6,B:2.

我的最终输出字符串应该 return 按字母顺序排列的键。排除求和后值为0的键。

输入:new String[] {"X:-1", "Y:1", "X:-4", "B:3", "X:5"}

输出:B:3,Y:1

输入:new String[] {"Z:0", "A:-1"}

输出:A:-1

尝试过的代码:

public static String Output(String[] strArr) {
       //strArr = new String[] {"X:-1", "Y:1", "X:-4", "B:3", "X:5"};
        Map<String, Double> kvs =
                Arrays.asList(strArr)
                    .stream()
                    .map(elem -> elem.split(":"))
                    .collect(Collectors.toMap(e -> e[0], e -> Double.parseDouble(e[1])));
        
        kvs.entrySet().forEach(entry->{
            System.out.println(entry.getKey() + " " + entry.getValue());  
         });
        
        return strArr[0];
      }

错误:

Exception in thread "main" java.lang.IllegalStateException: Duplicate key -1.0

我该如何解决这个问题?

您应该在第一个流中声明合并策略:

.collect(Collectors.toMap(e -> e[0], e -> Double.parseDouble(e[1]), Double::sum));

然后按零值过滤地图:

  .filter(s-> s.getValue() != 0)

按键排序使用:

   .sorted(Map.Entry.comparingByKey())

结果代码:

   String [] strArr = new String[] {"X:-1", "Y:1", "X:-4", "B:3", "X:5"};
    Map<String, Double> kvs =
            Arrays.asList(strArr)
                    .stream()
                    .map(elem -> elem.split(":"))
                    .collect(Collectors.toMap(e -> e[0], e -> Double.parseDouble(e[1]), Double::sum));

    kvs.entrySet().stream()
            .filter(s-> s.getValue() != 0)
            .sorted(Map.Entry.comparingByKey())
            .forEach(entry->{
        System.out.println(entry.getKey() + " " + entry.getValue());w
    });

它对我有用,我使用 Integer 而不是 double 和 summaringInt() 函数求和具有相同键的值:

        String[] strArr = new String[] { "X:-1", "Y:1", "X:-4", "B:3", "X:5" };

    Map<String, IntSummaryStatistics> collect = Arrays.asList(strArr)
        .stream()
        .map(elem -> elem.split(":"))
        .collect(Collectors.groupingBy(e -> e[0], Collectors.summarizingInt(e -> Integer.parseInt(e[1]))));

    System.out.println("Result:");

    collect.entrySet().stream()
        .filter(e -> e.getValue().getSum() != 0)
        .sorted(Map.Entry.comparingByKey())
        .forEach(e -> System.out.println("Key : " + e.getKey() + ", Value : " + e.getValue().getSum()));

也可以使用Collectors.groupingBy + Collectors.summingDouble通过收集到TreeMap:

来构建排序的kvs映射
String [] strArr = new String[] {"X:-1", "Y:1", "X:-4", "B:3", "X:5"};
Map<String, Double> kvs = Arrays.stream(strArr)
        .map(elem -> elem.split(":"))
        .collect(Collectors.groupingBy(
            e -> e[0], 
            TreeMap::new, // sort by key
            Collectors.summingDouble(e -> Double.parseDouble(e[1]))
        ));
System.out.println(kvs);  // entries with 0 value yet to be removed
// output
// {B=3.0, X=0.0, Y=1.0}

如果只需要打印上述格式的地图,不带0值,可以这样做:

System.out.println(
    kvs.entrySet().stream()
        .filter(e -> e.getValue() != 0)
        .map(e -> new StringBuilder(e.getKey()).append(':').append(e.getValue().intValue()) )
        .collect(Collectors.joining(","))
);
// output
// B:3,Y:1

如果需要从 kvs 中删除 0 个值,则可以将 removeIf 应用于其条目集:

kvs.entrySet().removeIf(e -> e.getValue() == 0);
System.out.println(kvs);
// output
// {B=3.0, Y=1.0}