Django-Filter 并使用数组进行查询

Question

我有一个简单的问题：目前我可以这样做以从我的后端获取一个对象：

http://127.0.0.1:8000/api/v1/boats/boats?id=10
http://127.0.0.1:8000/api/v1/boats/boats?home_port=98&id=5

但我想根据 ID 列表或 home_ports 列表获取一组船，我已经尝试过：

http://127.0.0.1:8000/api/v1/boats/boats?id=10,11
http://127.0.0.1:8000/api/v1/boats/boats?id_in=10,11
http://127.0.0.1:8000/api/v1/boats/boats?id=10,id=11
http://127.0.0.1:8000/api/v1/boats/boats?id=10&id=11

但是这些都不行。使用 django-filter 执行此操作的最佳方法是什么，URL 规则是如何定义的？

这是我的观点：

class BoatList(generics.ListCreateAPIView):
    permission_classes = (IsOwnerOrReadOnly,)
    serializer_class = BoatSerializer
    queryset = Boat.objects.all()
    filter_backends = (filters.DjangoFilterBackend,)
    filter_fields = ('id', 'home_port',)

我标记为 100% 接受的解决方案回答了我的问题，但我最终实现了基于另一个 post 我发现使用过滤器的不同的东西：

class ListFilter(Filter):

    def filter(self, qs, value):
        if not value:
            return qs

        self.lookup_type = 'in'
        values = value.split(',')
        return super(ListFilter, self).filter(qs, values)

class BoatFilter(FilterSet):
    ids = ListFilter(name='id')

    class Meta:
        model = Boat
        fields = ['home_port', 'ids']


class BoatList(generics.ListCreateAPIView):
    permission_classes = (IsOwnerOrReadOnly,)
    serializer_class = BoatSerializer
    queryset = Boat.objects.all()
    filter_backends = (filters.DjangoFilterBackend,)
    filter_class = BoatFilter

    def perform_create(self, serializer):
        serializer.save(owner=self.request.user)

Answer 1

试试这个：

url: http://127.0.0.1:8000/api/v1/boats/boats?id=10,11

class BoatList(generics.ListCreateAPIView):
    permission_classes = (IsOwnerOrReadOnly,)
    serializer_class = BoatSerializer
    queryset = Boat.objects.filter(id__in=request.GET.getlist('id')) #<------
    filter_backends = (filters.DjangoFilterBackend,)
    filter_fields = ('id', 'home_port',)

Answer 2

doniyor的回答很贴切。但我猜 request 在使用它的地方将不可用。

还有另一种方法 this.You 可以覆盖 get_queryset 方法。这可以按如下方式完成：

class BoatList(generics.ListCreateAPIView):
    permission_classes = (IsOwnerOrReadOnly,)
    serializer_class = BoatSerializer
    filter_backends = (filters.DjangoFilterBackend,)
    filter_fields = ('id', 'home_port',)

    def get_queryset(self):
        id_list = self.request.GET.getlist("id")
        if not id_list:
            return []
        return Boat.objects.filter(id__in=id_list)

Answer 3

您刚刚创建了一个过滤器class

    class NumberInFilter(BaseInFilter, NumberFilter):
          pass


    class myFilter(FilterSet):
          id__in = NumberInFilter(field_name='id', lookup_expr='in')

          class Meta:
                model = Boat

在视图集中使用

           filter_class = myFilter

你可以看到django-filter的这篇文档： https://django-filter.readthedocs.io/en/master/ref/filters.html?highlight=BaseInFilter

Django-Filter 并使用数组进行查询

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python

api

django

django-filter

django-rest-framework