如何从 html 内容打印特定值？

Question

下面是 HTML 内容我想要 HTML 内容

中唯一可用的值

    <div class="list-group-item">
     <div class="row">
      <div class="col" style="min-width: 0;">
       <h2 class="h5 mt-0 text-truncate">
        <a class="text-warning" href="www.example.com">
         Ram
        </a>
       </h2>
       <p class="mob-9 text-truncate">
        <small>
         <i class="fa fa-fw fa-mobile-alt">
         </i>
         Contact:
        </small>
        010101010
       </p>
       <p class="mb-2 text-truncate">
        <small>
         <i class="fa fa-fw fa-map-marker-alt">
         </i>
         Location:
        </small>
        5th lane, kamathipura, Kamathipura
       </p>
        </a>
       </p>
      </div>
     </div>
    </div>

我的代码是-

import pandas as pd
import requests
from bs4 import BeautifulSoup as soup
url = requests.get("www.example.com")
page_soup = soup(url.content, 'html.parser')
name = shop.findAll("div", {"class": "list-group-item"})
print(name.h2.text)
number = shop.findAll("p", {"class": "fa fa-fw fa-map-marker-alt"})
print(?)
location = shop.findAll("p", {"class": "fa fa-fw fa-map-marker-alt"})
print(?)

我需要使用 python -

输出

'Ram', '010101010', '5th lane, kamathipura, Kamathipura'

Answer 1

你试过了吗location.get_text()？

您可以去 here 阅读更多相关信息。

Answer 2

使用标签和class标识符，您可以抓取您想要的区域内的所有内容。然后使用内容索引，您应该能够 select 您想要的确切内容，如下所示：

from bs4 import BeautifulSoup
url = 'myhtml.html'
with open(url) as fp:
    soup = BeautifulSoup(fp, 'html.parser')
    contnt1 = [soup.find('a').contents[0].replace(' ','').replace('\n','')]
    contnt2 = [x.contents[2].replace(' ', '').replace('\n', '') for x in soup.find_all("p", "text-truncate")]
    print(*(contnt1 + contnt2))

如何从 html 内容打印特定值？

how to print a particular value from html content?

python

xcode

python-2.7

python-3.x

python-requests