R中直方图中的非均匀箱

Question

我想将数据集（数值向量）分成一些区间，并生成频率直方图以查看哪些值落入每个区间。如果我使用 hist(dataset, breaks = 10) 这会将数据集分成 10 个相等的间隔。相反，我想将数据集分成（例如）10 个箱子，每个间隔至少包含 5% 的数据点。

Answer 1

您可以使用 quantile() 函数来定义大小相等的 bin。

这里有一个关于指数分布数据的例子：

# Seed for the random number generation (for repeatability)
seed = 1313

# Sample size
N = 150

# Size of each bin (as proportion of N)
binsize = 0.05

# Sample data
x = rexp(N)

# Regular histogram (equal-width bins)
hist(x, breaks=20, freq=TRUE, main="Histogram on 20 equal-width bins", col="red")

# Quantiles of size `binsize`
x.quantiles = quantile(x, probs=seq(0, 1, binsize))

# Histogram on the equal-size breaks
hist(x, breaks=x.quantiles, freq=TRUE, main=paste("Approx. equal-size-bin 'Histogram' (bin-size=", binsize*100, "% of ", N, ")", sep=""), col="cyan")

R中直方图中的非均匀箱

Non-uniform bins in Histogram in R

r

histogram