从数据集中查找重叠的日期范围

Question

p_id    book_num conf_num   arrival_dt  departure_dt    create-dt   room_num
353     21807    3328568    19-JUN-15   21-JUN-15       27-JUN-15   2408
353     21807    3328562    18-JUN-15   20-JUN-15       27-JUN-15   2408

在上面的例子中，arrival_dt 和 departure_dt 重叠了 2 个不同的同一房间号的确认号码 2408

我还想排除下面的记录集，其中 arrival_dt 和 departure_dt 相同

p_id    book_num conf_num   arrival_dt  departure_dt    create-dt   room_num
353     21802    3328508    18-JUN-15   21-JUN-15       27-JUN-15   1909    
353     21802    3328555    18-JUN-15   21-JUN-15       27-JUN-15   1909

你能帮我用 SQL 逻辑在 table

中找到这类记录吗

Answer 1

正确的逻辑是先到先走a先到先走。您可以使用自联接或 where 子句来执行此操作。

如果您只想要记录：

select r.*
from records r
where exists (select 1
              from records r2
              where r2.pid = r.pid and
                    r2.arrival_dt >= r.departure_dt and
                    r2.departure_dt <= r.arrival_dt
             );

Answer 2

SELECT tbl.*
FROM table tbl
JOIN table tbl1 ON tbl.p_id= tbl1.p_id
WHERE tbl.Arrival_dt <= tbl1.Departure_dt
    AND tbl.Departure_dt >= tbl1.Arrival_dt

Answer 3

SQL Fiddle

Oracle 11g R2 架构设置:

CREATE TABLE TEST ( p_id, book_num, conf_num, arrival_dt, departure_dt, create_dt, room_num ) AS
          SELECT 353, 21807, 3328568, DATE '2015-06-19', DATE '2015-06-21', DATE '2015-06-27', 2408 FROM DUAL
UNION ALL SELECT 353, 21807, 3328562, DATE '2015-06-18', DATE '2015-06-20', DATE '2015-06-27', 2408 FROM DUAL
UNION ALL SELECT 353, 21802, 3328508, DATE '2015-06-18', DATE '2015-06-21', DATE '2015-06-27', 1909 FROM DUAL
UNION ALL SELECT 353, 21802, 3328555, DATE '2015-06-18', DATE '2015-06-21', DATE '2015-06-27', 1909 FROM DUAL
UNION ALL SELECT 353, 21801, 3328444, DATE '2015-06-17', DATE '2015-06-21', DATE '2015-06-27', 2000 FROM DUAL
UNION ALL SELECT 353, 21801, 3328445, DATE '2015-06-18', DATE '2015-06-20', DATE '2015-06-27', 2000 FROM DUAL
UNION ALL SELECT 353, 21803, 3328446, DATE '2015-06-19', DATE '2015-06-20', DATE '2015-06-27', 2001 FROM DUAL
UNION ALL SELECT 353, 21804, 3328447, DATE '2015-06-20', DATE '2015-06-21', DATE '2015-06-27', 2001 FROM DUAL;

查询 1:

SELECT *
FROM   TEST t
WHERE  EXISTS ( SELECT 'X'
                FROM   TEST x
                WHERE  x.room_num     = t.room_num
                AND    x.arrival_dt   < t.departure_dt
                AND    x.departure_dt > t.arrival_dt
                AND NOT (    x.arrival_dt   = t.arrival_dt
                         AND x.departure_dt = t.departure_dt ) )

Results:

| P_ID | BOOK_NUM | CONF_NUM |             ARRIVAL_DT |           DEPARTURE_DT |              CREATE_DT | ROOM_NUM |
|------|----------|----------|------------------------|------------------------|------------------------|----------|
|  353 |    21807 |  3328568 | June, 19 2015 00:00:00 | June, 21 2015 00:00:00 | June, 27 2015 00:00:00 |     2408 |
|  353 |    21807 |  3328562 | June, 18 2015 00:00:00 | June, 20 2015 00:00:00 | June, 27 2015 00:00:00 |     2408 |
|  353 |    21801 |  3328444 | June, 17 2015 00:00:00 | June, 21 2015 00:00:00 | June, 27 2015 00:00:00 |     2000 |
|  353 |    21801 |  3328445 | June, 18 2015 00:00:00 | June, 20 2015 00:00:00 | June, 27 2015 00:00:00 |     2000 |

从数据集中查找重叠的日期范围

Find overlapping date range from a data set

sql

oracle

date

range