SELECT 两个表中的 COUNT 不起作用

SELECT COUNT from two tables is not working

我有两个 table - 第一个 table 是“项目”:

p_id p_name
1 test1
2 test2
3 test2
4 test3

p_name 不是唯一的

第二个table是“员工”:

e_id jan feb mar apr may
1 2 2 3 3 4
2 1 1 3 3 2
3 1 3 2 3 3
4 4 3 2 3 4

我想根据姓名计算 p_name 员工人数

我的工作:

select 
    p.id, p.name, 
    count(e1.jan) as e1, 
    count(e2.feb) as e2, 
    count(e3.mar) as e3  
from 
    projects p 
left join 
    employee e1 on (e1.jan = p.id) 
left join 
    employee e2 on (e2.feb = p.id) 
left join 
    employee e3 on (e3.mar = p.id) 
where 
    p.name = 'test2' 
group by 
    p.name;

但是没用。它没有 return 预期的数字。

如果您能提供您希望看到的示例数据集,您会更清楚地了解您的目标。

但是,您可以尝试使用每个月的 apply() 进行如下操作

select p.id,p.[name], e1.qty, e2.qty, e3.qty, e4.qty, e5.qty
from 
projects p 
outer apply ( select count(*) qty from employee e where e.jan = p.id )e1
outer apply ( select count(*) qty from employee e where e.feb = p.id )e2
outer apply ( select count(*) qty from employee e where e.mar = p.id )e3
outer apply ( select count(*) qty from employee e where e.apr = p.id )e4
outer apply ( select count(*) qty from employee e where e.may = p.id )e5
where p.name = 'test2' 
select count(jan) from employee where jan in (
select p_id from projects where p_name = 'test1') 

您可以这样做并单独获取每一列的输出

很清楚为什么它不起作用。仅以项目 3 以及二月和三月为例。你从一行开始,项目。然后您加入了项目 3 的 2 月员工,其中有两个,所以现在您有两行。然后你对 march 做同样的事情,同样有两行,但是因为你在 Feb 加入后有两行你现在有 2*2 行,这是四行。您需要在加入之前聚合,而不是之后。

我会使用外部应用方法。但更容易理解的选择可能是聚合然后加入。

select 
    p.id, p.name, 
    e1.jan as e1, 
    e2.feb as e2, 
    e3.mar as e3  
from 
    projects p 
left join 
    (SELECT jan AS pid, COUNT(*) AS jan FROM employee) e1 on (e1.pid = p.id) 
left join 
    (SELECT feb AS pid, COUNT(*) AS feb FROM employee) e2 on (e2.pid = p.id)
left join 
    (SELECT mar AS pid, COUNT(*) AS mar FROM employee) e3 on (e3.pid = p.id)
left join 
    (SELECT apr AS pid, COUNT(*) AS apr FROM employee) e4 on (e4.pid = p.id)
where 
    p.name = 'test2' 

我完全同意@sTTu 的评论 - 所选择的设计是不可扩展的,一旦“新年”开始,就会 运行 出现问题。

出于好奇,我试图想出一个解决方案,如下所示:

(SQL-服务器 - 但也应该在 MySql)

中工作
SELECT name, SUM(jan) Jan, SUM(feb) feb, SUM(mar) mar FROM (
  SELECT id, name, 
    (SELECT count(*) FROM employee WHERE jan=id) jan,
    (SELECT count(*) FROM employee WHERE feb=id) feb,
    (SELECT count(*) FROM employee WHERE mar=id) mar
  from projects ) tbl
group by name;

这是一个工作片段:https://rextester.com/TBWZA82894

结果:

name Jan feb mar
test1 2 1 0
test2 1 3 4
test3 1 0 0

或者,您可以更简单地这样做:

SELECT name,
  COUNT(CASE WHEN jan=id THEN 1 END) jan,
  COUNT(CASE WHEN feb=id THEN 1 END) feb,
  COUNT(CASE WHEN mar=id THEN 1 END) mar
FROM employee 
INNER JOIN projects ON id>0
GROUP BY name

在此处查看演示:https://rextester.com/DEUUE59264