在 Spring Boot 上设置(OAuth 令牌)授权 Header

set the (OAuth token) Authorization Header on SpringBoot

我必须发送一个 Get 请求来请求令牌 URL 这些 Headers:

Content-Type: application/x-www-form-urlencoded
Authorization:
        OAuth oauth_consumer_key="your_consumer_key",
        oauth_nonce="random_string_or_timestamp",
        oauth_signature="your_consumer_secret&",
        oauth_signature_method="PLAINTEXT",
        oauth_timestamp="current_timestamp",
        oauth_callback="your_callback"
User-Agent: some_user_agent

我试过这段代码:

HttpURLConnection conn = (HttpURLConnection) url.openConnection();
        conn.setDoOutput(true);
        conn.setRequestMethod("GET");

        conn.setRequestProperty("Authorization: OAuth oauth_consumer_key", "BaeUqWMTmCxjeJj9mkJr");
        conn.setRequestProperty("Authorization: oauth_nonce", "random_string_or_timestamp");
        conn.setRequestProperty("Authorization: oauth_signature", "ZWglyBtJasnJBqVndzyduYJggCduKeYks&");
        conn.setRequestProperty("Authorization: oauth_timestamp", String.valueOf(new Date()));
        conn.setRequestProperty("Authorization: oauth_callback", "http://localhost:8080");
        conn.setRequestProperty("User-Agent", "test");

        int statusCode = conn.getResponseCode();
        System.out.println("Response from WA Gateway: \n");
        System.out.println("Status Code: " + statusCode);
        BufferedReader br = new BufferedReader(new InputStreamReader(
                (statusCode == 200) ? conn.getInputStream() : conn.getErrorStream()
        ));
        String output;
        while ((output = br.readLine()) != null) {
            System.out.println(output);
        }
        conn.disconnect();

但是我得到这个错误:

Illegal character(s) in message header field: Authorization: OAuth oauth_consumer_key

问题是您的请求格式不正确。由于它是 OAuth 请求的 GET 版本,这里有一个来自 RFC5849 的例子,说明如何做到这一点

GET /example/path?oauth_consumer_key=0685bd9184jfhq22& oauth_token=ad180jjd733klru7&oauth_signature_method=HM AC-SHA1&oauth_signature=wOJIO9A2W5mFwDgiDvZbTSMK%2FPY% 3D&oauth_timestamp=137131200&oauth_nonce=4572616e48616 d6d65724c61686176&oauth_version=1.0 HTTP/1.1

Sp,按照上面的格式在setRequestProperty中设置一个Authorizationheader:

...
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
String yourUrl = "http://yourwebsite.com";
String currentSeconds = 1618496867; // current seconds
String authorizationValue = "OAuth oauth_consumer_key=\"BaeUqWMTmCxjeJj9mkJr\",
    oauth_nonce=\"1618496867\",
    oauth_signature=\"ZWglyBtJasnJBqVndzyduYJggCduKeYks&\",
    oauth_signature_method=\"PLAINTEXT\",
    oauth_timestamp=\"1618496867\",
    oauth_callback=\"http://localhost:8080\""

conn.setRequestProperty("Authorization", authorizationValue);
conn.setDoOutput(true);
conn.setRequestMethod("GET");
...

我使用 Postman 客户端为我的 OAuth 身份验证服务器测试了一个类似的请求,它运行良好。

这些不是headers,你得计算一下..像这样

https://twittercommunity.com/t/solved-java-oauth-request-token-flow-example-without-libraries/1440