用户输入一定次数 - bash 脚本

Question

我定义了一个函数如下。

无输入-退出
输入 'n'-> 退出
输入'y'->继续下一步
输入非'y'或'n' -> 重试3次仍输入错误 -> 退出

我无法实现最后的重试部分。有人可以帮忙吗？

my_func()
  {
   read -p "Still want to continue (y/n)? : " userin
   userin=${userin,,}
   if [ -z "$userin" ];then
        echo "No input"
        exit 1
   elif [ $userin == "n" ]; then
        exit 1
   elif [ $userin == "y" ]; then
        echo "Next step starting
        return
   else
        echo "You entered $userin - give proper input(y/n)"

   fi
}

Answer 1

你会尝试以下方法吗：

my_func() {
     for ((i = 0; i < 3; i++)) {
         read -p "Still want to continue (y/n)? : " userin
         if [[ -z $userin ]]; then
             echo "No input"
             exit 1
         elif [[ $userin = "n" ]]; then
             exit 1
         elif [[ $userin = "y" ]]; then
             echo "Next step starting"
             return
         else
             echo "You entered $userin - give proper input(y/n)"
         fi
    }
    exit 1
}

用户输入一定次数 - bash 脚本

user input for certain number of time- bash script

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