如何增加函数中的循环次数？

Question

我这里有一个代码

letters = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
ret = ""
for i in range(26):
  for j in letters:
    ret += f"({letters[i]},{j})"
print(ret)

#Output: 
(a,a)(a,b)(a,c)(a,d)(a,e)(a,f)(a,g)(a,h)(a,i)(a,j)(a,k)(a,l)(a,m)(a,n)(a,o)(a,p)...(z,y)(z,z)

我想解决的问题是：

当我尝试增加排列数时，例如从 2 位数增加到 3 位数，我必须添加另一个循环。当我想将其实现为函数时，如何在增加位数时增加循环数，谁能帮忙:(

这是我尝试将位数从 2 增加到 3 时所做的：

for i in range(26):
  for k in range(26):
    for j in letters:
      ret += "(" + str(letters[i]) + "," + str(letters[k]) + "," + j + ")"
print(ret)

#Output
(a,a,a)(a,a,b)(a,a,c)(a,a,d)(a,a,e)(a,a,f)(a,a,g)(a,a,h)(a,a,i)(a,a,j)(a,a,k)(a,a,l)(a,a,m)...(z,z,z)

如何在函数中实现它？

Answer 1

您可以像这样使用 itertools 实现此目的

import itertools

def perm_func(arr, x):
    ret_str = ""
    p for p in itertools.product(arr, repeat=x):
        ret_str += str(p)

    return ret_str

如何增加函数中的循环次数？

How to increase number of loops in a function?

python

loops

function

permutation