我在 zparseopts 中发现了错误还是我做错了

Question

今天下午我完成了对 document/solve zparseopts 的任务。我想我发现了 -K 选项的错误 - 或者我称之为 -KillYourself。

我认为 -K 没有正确处理标志选项。输出将先前存在的 key/value 对的二分之一偏向左侧，如下所示。

BASH / ZSH 大师可以确保我这样做是正确的吗？

使用 -K 以及其他选项和标志的预期行为：

Dictionary:

--key           -> greg
--flag          -> 
default         -> Mr. Yutz Was Here

使用 -K 且没有其他选项的预期行为：

Dictionary:

default         -> Mr. Yutz Was Here

奇怪的可能被破坏的行为：

Dictionary:

--key                   -> greg
--flag                  -> default
Mr. Yutz Was Here       ->

看起来关联数组向左“碰撞”了一半的值。

#!/usr/bin/env zsh


declare -a pargs        #numveric index array
declare -A paargs       #associative array - or dictionary

pargs=("Mr. Yutz Was Here")
paargs[default]="Mr. Yutz Was Here"

echo "\n=====\npargs currenty:\n$pargs"
echo "\n=====\npaargs currenty:\n$paargs"

# -K - KILL YOURSELF - and KEEP previous settings like defaults you pumped into the array before processing.  As long as they are not set below.  Then this is meaningless.
#      Seriously....if you use this you will want to kill yourself.  If you have a flag, the Associative array breaks.  Ugh.
#      to recreate bug, run without arguments.  Then run again with --flag --key FooBar.  Delete -K and do it again.
#      The "Dictionary Output will be borked."
# -D - DELETE - pops each item from the input and processes the next element as "the first one" of  if you want to be all shelly about it
# -E - NO ERROR - don't stop on an error.  keep going until done or -- is hit
# -a - ARRAY for the results indexed from 1
# -A - DICTIONARY for the results in key / value pairs.  Flags don't have values.  Just "presence"

zparseopts -D -E -a pargs -A paargs -flag -key:

printf "\n=====\nArray of Results:\n\n"

for ((i = 1; i <= $#pargs; i++)) 
do
    echo "item: $i \t-> $pargs[$i]"
done

echo "\n====="

printf "Dictionary:\n\n"
for key value in ${(kv)paargs}
do
    echo "$key \t-> $value"
done
echo "=====\n"

# Flag detection.
printf "flag=%s key=%s\n\n" ${pargs[(I)--flag]} ${paargs[--key]}
printf "%s\n\n" "$*"

这符合我的预期：不带 -K 的输出：

greg@api:~/projects/test_swarm$ ./zsh_test.sh --flag --key greg

=====
pargs currenty:
1: Mr. Yutz Was Here

=====
paargs currenty:
default: Mr. Yutz Was Here

=====
Array of Results:

item: 1         -> --flag
item: 2         -> --key
item: 3         -> greg

=====
Dictionary:

--key   -> greg
--flag  -> 
=====

flag=1 key=greg

带-K的输出：

greg@api:~/projects/test_swarm$ ./zsh_test.sh --flag --key greg

=====
pargs currenty:
1: Mr. Yutz Was Here

=====
paargs currenty:
default: Mr. Yutz Was Here

=====
Array of Results:

item: 1         -> --flag
item: 2         -> --key
item: 3         -> greg

=====
Dictionary:

--key   -> greg
--flag  -> default
Mr. Yutz Was Here       -> 
=====

flag=1 key=greg

Answer 1

问题是关联数组中值的打印输出。尝试用这个替换 paargs for 循环：

printf 'paargs %s: %s\n' "${(kv@)paargs}"

显着的变化是增加了双引号和@参数扩展标志。 zsh 通常对引用非常宽容，但在某些情况下它会有所不同。

使用 typeset 内置函数通常更容易显示变量值：

typeset -p pargs paargs

（元注释：我们需要 zparseopts 标签吗？）

我在 zparseopts 中发现了错误还是我做错了

Have I found a bug in zparseopts or am I doing this wrong

zsh