如何在大字符串中找到 link

Question

我想找一个link喜欢

在一个大字符串中，但有很多 link，我希望所有以 https://whosebug.com/questions/ 开头的 link 字符串看起来像


某事
所以我的问题是如何找到不完整的字符串？

Answer 1

试试这个：

import re
  
def Find(string):
  
    # findall() has been used 
    # with valid conditions for urls in string
    regex = r"(?i)\b((?:https?://|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))"
    url = re.findall(regex,string)      
    return [x[0] for x in url if "whosebug.com/questions" in x[0]]
      
# Driver Code
string = 'content_license CC BY-SA 4.0 link https//whosebug.com/questions/26325943/many-threads-to-write-log-file-at-same-time-in-python title Many threads to writ'
print(Find(string))

这输出：['whosebug.com/questions/26325943/many-threads-to-write-log-file-at-same-time-in-python']，这就是我假设你想要的。

如何在大字符串中找到 link

How to find a link in a big string

python

find

python-3.x