通过循环将列表中的嵌套字典值与彼此进行比较？

Question

我有一个程序可以收集一些统计数据并计算一些球队在一个篮球赛季中的 ELO。当我尝试计算每个团队的预期获胜百分比时，问题仍然存在，但这些值都存储在同一个嵌套字典列表中：eList=[{'Perth': 1715}, {'Melbourne': 1683}, {'Phoenix': 1648}, {'Sydney': 1605}, {'The Hawks': 1573}, {'Brisbane': 1573}, {'Adelaide': 1523}, {'New Zealand': 1520}, {'Cairns': 1477}]。我试过嵌套的 for 循环一次迭代两个值，但它会导致错误。我正在尝试遍历列表字典中各个团队的所有 ELO 值，然后将它们相互交叉比较，以便可以将这些值输入我的其他函数并输出结果：

def expected_result(rating1, rating2):
    exp = (rating2 - rating1)/400.
    Ea = 1/(1 + math.pow(10, exp))
    Eb = 1/(1 + math.pow(10, -exp))
    return Ea*100, Eb*100

Answer 1

import math
eList=[{'Perth': 1715}, {'Melbourne': 1683}, {'Phoenix': 1648}, {'Sydney': 1605}, {'The Hawks': 1573}, {'Brisbane': 1573}, {'Adelaide': 1523}, {'New Zealand': 1520}, {'Cairns': 1477}]
val=[list(i.values())[0] for  i in eList]
#extracting just the values from eList

from itertools import combinations
g=list(combinations(val, 2))
#pairing up two teams values
def expected_result(rating1, rating2):
    exp = (rating2 - rating1)/400.
    Ea = 1/(1 + math.pow(10, exp))
    Eb = 1/(1 + math.pow(10, -exp))
    return Ea*100, Eb*100

for i in g:
    print(expected_result(*i))
    #unpacking each tuple into function

首先，我们需要在不重复的情况下对每个团队进行配对，一旦我们有了元组列表，我们就可以使用 for 循环解压缩输出：

(54.592192278048365, 45.407807721951635)
(59.52430396515719, 40.47569603484281)
(65.32171672188699, 34.67828327811303)
(69.36879164219654, 30.63120835780346)
(69.36879164219654, 30.63120835780346)......

通过循环将列表中的嵌套字典值与彼此进行比较？

Comparing nested dictionary values within a list against eachother via loop?

python

logic

dictionary

nested

list