有没有办法将行号和列号映射到 python 中的相应数字

Question

嘿，所以我试图用数字绘制出第一行和第一列，但在这里发现了一些困难

output = " "
column_count = 0
row_count = 1
for row in range(10):
output = " "
 for column in range(20):
    if (row == 0):
        while column_count <= 20:
            print(column_count, end = " ")
            column_count += 1
    elif (column == 0):
        while row_count <= 10:
            print(row_count)
            row_count += 1
    else:
        output += "x"

print(output)

这是我的输出

so something like this but mapped out perfectly

Answer 1

根据我对你问题的理解，你实际上是在寻找一个网格，就像你在乘法表中找到的一样，除了 'X' 而不是产品。

以下是 this answer to the question How to print a 10*10 times table as a grid? 的改编版。

# Set Number of Rows and Columns
cols = 21
rows = 11

# Determine width of each column based on largest column
space_fmt = f'{{:>{len(str(cols)) + 1}}}'

# Print Header Row
print(''.join(space_fmt.format(i) for i in range(0, cols)))
# Print Remaining Rows
for y in range(1, rows):
    # Print First Number
    print(space_fmt.format(y), end='')
    # Print Xes
    print(''.join([space_fmt.format('X') for _ in range(1, cols)]))

只有 for 循环的答案，没有加入列表理解

# Set Number of Rows and Columns
cols = 21
rows = 11

# Determine width of each column based on largest column
space_fmt = f'{{:>{len(str(cols)) + 1}}}'

# Print Header Row
for i in range(0, cols):
    print(space_fmt.format(i), end='')
print()  # New Line
# Print Remaining Rows
for y in range(1, rows):
    # Print First Number
    print(space_fmt.format(y), end='')
    # Print Xes
    for col in range(1, cols):
        print(space_fmt.format('X'), end='')
    print()  # New Line

有没有办法将行号和列号映射到 python 中的相应数字

is there a way to map the row and column numbers to corresponding numbers in python

python

mapping

loops

for-loop