Python

Question

我正在努力获得我想要的输出。我有一个列表和一个字典，如下所示：

h3_rules = [[{'LA'}, {'KE'}, 0.9468308801441875], [{'KE'}, {'LA'}, 0.9650949173300674], [{'EH'}, {'LA', 'KE'}, 0.9136231884057971], [{'LA'}, {'EH', 'KE'}, 0.9468308801441875], [{'KE'}, {'LA', 'EH'}, 0.9650949173300674], [{'LA', 'EH'}, {'KE'}, 0.9471153846153846], [{'EH', 'KE'}, {'LA'}, 0.9650949173300674], [{'LA', 'KE'}, {'EH'}, 1.0], [{'EH'}, {'KE'}, 0.9466666666666667], [{'KE'}, {'EH'}, 1.0], [{'LA'}, {'EH'}, 0.99969960949234], [{'EH'}, {'LA'}, 0.9646376811594203]]

and

h3_S = {'EH': [0.33326893353941267], 'KE': [0.31549459041731065], 'LA': [0.321580370942813], 'PR': [0.029656105100463678]}

如果嵌套列表的第一个索引与字典键匹配，我想将一个值附加到嵌套列表。我要附加的值是通过将嵌套列表的最后一个索引除以相应字典键的值来计算的。下面是我希望使用第一个嵌套列表作为示例实现的手写示例。嵌套列表的第一个索引设置为“LA”：

h3_rules = [[{'LA'}, {'KE'}, 0.9468308801441875, (0.9468308801441875/0.321580370942813], ...]

目前我有下面的代码，但我一直在检查列表值是否与键匹配并使用该值进行除法。

# For every rule in rules
for i in h3_rules:
  # Check if the first index for every rule matches a dictionary key
  if h3_rules[i][0] == ?:
    # If there is a match append the newly calculated value based on the key value to the list
    h3_rules[i].append(h3_rules[i][-1] / ?)
  print(h3_rules)

我在 Stack overflow 中进行了广泛的查找，但找不到任何内容。关于如何实现理想结果的任何想法？

Answer 1

根据h3_rules的定义方式，首先需要验证第一个索引是否是set的实例，获取集合的第一个值，然后追加对应部门

for h in h3_rules:
    first_element = next(iter(h[0])) if isinstance(h[0], set) else None
    if first_element is not None: h.append(h[-1]/h3_S[first_element][0])

Python - 根据匹配列表和嵌套集提取字典值

Python - Extract dictionary value based on matching list and nested set

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