Oracle SQL 组合 table 信息并创建输出

Question

我在 Oracle SQL 开发人员中有两个表，我正在尝试弄清楚如何显示“fname, ssn”和员工对应的经理“fname, snn”。下面是我创建的表格，但我似乎无法获得与其后续经理相对应的员工信息。

员工Table

| EMPLOYEE# | FNAME | LNAME | SNN  | DEPARTMENT_NAME | JOB_TITLE |
| 1         | jim   | box   |  11  | accounting      | person    |
| 2         | james | boer  |  22  | IT              | manager   |
| 3         | tom   | jo    |  33  | IT              | person    |
| 4         | tim   | quo   |  44  | accounting      | manager   |

部门Table

| MANAGER_EMPLOYEE# | DEPARTMENT_NAME |
| 2                 | IT              |
| 4                 | accounting      |

期望的输出

| EMPLOYEE NAME  | Employee SSN | MANAGER NAME | MANAGER SSN |
| jim box        | 11           | james boer   |  22         |
| tom jo         | 33           | tim quo      |  44         |

这就是我目前所拥有的。它只是为了显示员工信息和经理#，因为我不确定如何将其实际发送到 link 到经理姓名，然后显示为我想要的输出

select employee#, fname, lname, employee.department_name, manager_employee# from employee left outer join department on employee.employee# = department.manager_employee#
union
select employee#, fname, lname, employee.department_name, manager_employee# from employee right outer join department on employee.employee# = department.manager_employee#;

Answer 1

看起来你需要这个：

select 
  emp.employee#, 
  emp.fname, 
  emp.lname, 
  emp.snn,
  emp.department_name, 
  dep.manager_employee#,
  man.fname as manager_fname,
  man.lname as manager_lname
from 
    employee emp
    left join department dep
        on emp.department_name = dep.department_name
    left join employee man
        on dep.manager_employee# = man.employee#;

Oracle SQL 组合 table 信息并创建输出

Oracle SQL combining table information and creating output

sql

oracle

oracle-sqldeveloper