oracle 中的 Pivot 没有给出预期的结果

Question

我有一个 table 结果如下

我有一个 table 如下所示：

PE_ID	Phone_Num	Email
740	NULL	test@test.com
740	124567890	NULL

我正在尝试得到如下结果

PE_ID	Phone_Num	Email
740	124567890	test@test.com

我曾尝试使用以下 PIVOT 查询，但它无法正常工作

with rws as (
  select 740 type, NULL Phone_Num, 'test@test.com' email from dual union all
  select 740 type, '711692162' Phone_Num, NULL email from dual 
), rns as (
  select row_number () over ( order by type ) rn,
         r.*
  from   rws r
)
  select * from rns
  pivot (
    min ( type ) Pe_ID, min ( Phone_Num ) Phone_Num, min ( email ) email
    for rn in (1)

);

给出的结果如下

PE_ID_1	Phone_Num_1	Email_1
740	NULL	test@test.com

请任何人为我指出预期结果的正确方向

Answer 1

您似乎想要按类型分组并查找最少的 phone 号码和电子邮件，并且 return 仅查找最少的类型。您不需要 PIVOT，只需聚合 return 第一行：

SELECT type,
       MIN( phone_num ) AS phone_num,
       MIN( email ) email
FROM   table_name
GROUP BY type
ORDER BY type
FETCH FIRST ROW ONLY

其中，对于示例数据：

CREATE TABLE table_name ( type, phone_num, email ) AS
  select 740, NULL, 'test@test.com' from dual union all
  select 740, '711692162', NULL from dual

输出：

TYPE PHONE_NUM EMAIL

740 711692162 test@test.com

db<>fiddle here

Answer 2

您根本不需要 PIVOT。您可以使用 FIRST_VALUE 分析功能获取第一个 phone 号码和电子邮件。

WITH
    rws
    AS
        (SELECT 740 TYPE, NULL Phone_Num, 'test@test.com' email FROM DUAL
         UNION ALL
         SELECT 740 TYPE, '711692162' Phone_Num, NULL email FROM DUAL)
SELECT DISTINCT
       TYPE,
       FIRST_VALUE (phone_num IGNORE NULLS) OVER (ORDER BY TYPE)     AS phone_num,
       FIRST_VALUE (email IGNORE NULLS) OVER (ORDER BY TYPE)         AS email
  FROM rws;

   TYPE    PHONE_NUM            EMAIL
_______ ____________ ________________
    740 711692162    test@test.com

Answer 3

SELECT peid, listagg(phone_num) phone_num , 
      listagg(email) email FROM table1 GROUP BY peid;

oracle 中的 Pivot 没有给出预期的结果

Pivot in oracle is not giving the expected result

oracle

oracle19c