matlibplot 中两个向量之间的填充区域

Question

以下代码计算以下向量：方向 Vector (red) and two vectors (blues) which result by rotating the red vector 60顺时针和逆时针度数。

import matplotlib.pyplot as plt
import numpy as np


def Visualize(orienVector,vector1,vector2):
 # Create figure and subplot
 fig = plt.figure()
 ax = fig.add_subplot(1, 1, 1)

 # Plot data points
 #ax.scatter(vector1[0], vector1[1], color='blue')
 #ax.scatter(vector2[0], vector2[1], color='orange')

 # Set limits for x and y axes
 plt.xlim(-1, 1)
 plt.ylim(-1, 1)

 # ===== Important bits start here =====

 # Set properties of spines
 ax.spines['top'].set_color('none')
 ax.spines['left'].set_position('zero')
 ax.spines['right'].set_color('none')
 ax.spines['bottom'].set_position('zero')

 # Set axis tick positions
 ax.xaxis.set_ticks_position('bottom')
 ax.yaxis.set_ticks_position('left')

 # Set specific tick locations
 ax.set_xticks([-10,-5, 0, 5 , 10])
 ax.set_yticks([-10,-5, 0, 5 , 10])

 # ===== End Of Important Bits =====

 # Draw arrows
 ax.arrow(0, 0 , vector1[0][0], vector1[1][0], 
    head_width=0.03, 
    head_length=0.1, 
    lw=1, 
    fc='blue', 
    ec='blue', 
    length_includes_head=True)
    
 ax.arrow(0, 0 , vector2[0][0], vector2[1][0], 
    head_width=0.03, 
    head_length=0.1, 
    lw=1, 
    fc='blue', 
    ec='blue', 
    length_includes_head=True)

 ax.arrow(0, 0 , orienVector[0][0], orienVector[1][0], 
    head_width=0.03, 
    head_length=0.1, 
    lw=2, 
    fc='red', 
    ec='red', 
    length_includes_head=True)

 plt.show()

# rotation matrix clockwise
def rotMatrixClockWise(angle):
 c, s = np.cos(angle), np.sin(angle)
 R = np.array([[c, -s], [s, c]])
 return R 

# rotation matrix clockwise
def rotMatrixCounterClockWise(angle):
 c, s = np.cos(angle), np.sin(angle)
 R = np.array([[c, s], [-s, c]])
 return R  

# center of the poit of interests POIS
POI_X = [10,12,15,17,20,50]
POI_Y = [20,30,25,22,19,35]

# position of the pedestrian 
pedPostion = np.array([[3],[4]])

# range of the horisontal angel view
spanningAngle = np.radians(60)

# calculate the cone 
for angle in range(0,360,5):
 
    
 # calculating the component of orientation vector V0, where the length |V0| = 1 
 x0 = 5*np.cos(np.radians(angle))
 y0 = 5*np.sin(np.radians(angle)) 
 v0 = np.array([[x0],[y0]])
 
 v1 = rotMatrixCounterClockWise(spanningAngle).dot(v0) 
 v2 = rotMatrixClockWise(spanningAngle).dot(v0) 


 Visualize(v0,v1,v2)

这个向量的输出看起来像

我正在尝试填充蓝色矢量之间的区域以获得如下所示的圆锥体：

圆锥体头部(0,0)与圆弧的距离始终为5

但是，我无法让它工作。我是 Matlibplot 的新手

Answer 1

你可以通过分析找出圆弧中的点（圆的一部分，所以 y = +- (1-x^2)**0.5），将它们添加到由原点和末端定义的多边形中的红色和黄色向量，然后使用 https://matplotlib.org/stable/api/_as_gen/matplotlib.pyplot.fill.html.

此处是填充多边形的示例：https://matplotlib.org/stable/gallery/lines_bars_and_markers/fill.html#sphx-glr-gallery-lines-bars-and-markers-fill-py

Answer 2

也许不完全是您要查找的内容，但您可以在向量之间创建一个楔形。拟合一个椭圆并填充其间的坐标会更合适。这是楔形的示例。

import matplotlib.pyplot as plt, numpy as np
from matplotlib import patches
v1 = np.array((1, 2))
v2 = np.array((1, -2))
base = np.array((0, 0))
theta1 = np.rad2deg(np.arctan(v1[1] / v1[0]))
theta2 = np.rad2deg(np.arctan(v2[1] / v2[0]))

fig, ax = plt.subplots()

a, b = theta1, theta2 
if b > a:
   a, b = b, a
artist = patches.Arc(base, 
            width = 1,
            height = 1, 
            theta1 = a, 
            theta2 = b,
            color = 'green')
ax.arrow(*base,  *v1, color = 'black')
ax.arrow(*base,  *v2, color = 'black')
ax.arrow(*base, *(v2 + v1), color = 'red')
wedge = patches.Wedge(base, 
            r = 1,
            width = 1, 
            theta1 = theta2, 
            theta2 = theta1,
            color = 'green')
ax.add_patch(wedge)

fig.show()

matlibplot 中两个向量之间的填充区域

Fill area between two vectors in matlibplot

python

numpy

matplotlib

rotation

seaborn