如何使用 PHP 在 JSON Twitter V2 响应中获取用户名?
How to grab the username in the JSON Twitter V2 response using PHP?
例如,我可以使用下面的代码获取“文本”,但是我如何获取 includes > user 下的用户名“Lionek_Gaming”?
$tweets = json_decode($response);
foreach($tweets->data as $tweet) {
$text = $tweet->text;
echo $text;
}
Json 回应
{
"data": [
{
"author_id": "1169144412171055104",
"id": "1386731275160072192",
"text": "sell Bitcoin at sweet rates"
}
],
"includes": {
"users": [
{
"id": "1304731585112158209",
"name": "Lionek_official #BRG",
"username": "Lionek_Gaming"
}
]
},
}
尝试以下操作:
foreach($tweets->includes->users as $user) {
$username = $user->username;
echo $username;
}
例如,我可以使用下面的代码获取“文本”,但是我如何获取 includes > user 下的用户名“Lionek_Gaming”?
$tweets = json_decode($response);
foreach($tweets->data as $tweet) {
$text = $tweet->text;
echo $text;
}
Json 回应
{
"data": [
{
"author_id": "1169144412171055104",
"id": "1386731275160072192",
"text": "sell Bitcoin at sweet rates"
}
],
"includes": {
"users": [
{
"id": "1304731585112158209",
"name": "Lionek_official #BRG",
"username": "Lionek_Gaming"
}
]
},
}
尝试以下操作:
foreach($tweets->includes->users as $user) {
$username = $user->username;
echo $username;
}