TableView 在 Swift 中展开和折叠单元格

Question

您好，我看过关于这个问题的教程，我可以在我的 table 视图中打开和关闭点击的部分，但是如果一个部分打开并且我要打开另一个部分，我想要上一个要关了，我关不了

TableViewCodes

func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
    
    let section = sections[section]
    
    if section.isOpened {
        return section.options.count + 1
    } else {
        return 1
    }
}

func numberOfSections(in tableView: UITableView) -> Int {
    
    return sections.count
}

func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    
    if indexPath.row == 0 {
        
        guard let cell = tableView.dequeueReusableCell(withIdentifier: "headerCell", for: indexPath) as? HeaderView else {return UITableViewCell()}
        cell.backgroundColor = #colorLiteral(red: 0.9607108235, green: 0.9608257413, blue: 0.9606716037, alpha: 1)
        
        cell.titleLabel?.text = sections[indexPath.section].title
        return cell
        
    } else {
        
        guard let cell = tableView.dequeueReusableCell(withIdentifier: "customCell", for: indexPath) as? CustomTableViewCell else {return UITableViewCell()}
        cell.backgroundColor = #colorLiteral(red: 0.9607108235, green: 0.9608257413, blue: 0.9606716037, alpha: 1)
        
        cell.titleLabel?.text = sections[indexPath.section].options[indexPath.row - 1]
        return cell
    }
}

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {  
    tableView.deselectRow(at: indexPath, animated: true)
    sections[indexPath.section].isOpened = !sections[indexPath.section].isOpened
    tableView.reloadSections([indexPath.section], with: .none)
}

剖面模型

class Section {
    
    let title: String
    let options: [String]
    var isOpened: Bool = false
    
    init(title: String, options: [String], isOpened: Bool = false) {
        
        self.title = title
        self.options = options
        self.isOpened = isOpened
    }
}

ViewDidLoad

sections = [
    
    Section(title: "Spor Giyim 1", options: [1,2,3].compactMap({ return "Cell \([=13=])" }), isOpened: true),
    Section(title: "Spor Giyim 2", options: [1,2,3].compactMap({ return "Cell \([=13=])" }), isOpened: false),
    Section(title: "Spor Giyim 3", options: [1,2,3].compactMap({ return "Cell \([=13=])" }), isOpened: false),
    Section(title: "Spor Giyim 4", options: [1,2,3].compactMap({ return "Cell \([=13=])" }), isOpened: false)
    
]

Answer 1

您需要将它们全部重置为 false 然后切换点击部分的当前状态

let toSet = !sections[indexPath.section].isOpened
sections.forEach {
    [=10=].isOpened = false
}
sections[indexPath.section].isOpened = toSet
tableView.reloadData()

Answer 2

在 viewController 中存储对任何打开的部分的引用，使用它将其重置为关闭，然后重新加载该部分和您要打开的部分：

class myVC: UIViewController {
  var openSection: Int?
  // rest of the VC...
}

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {  
    tableView.deselectRow(at: indexPath, animated: true)
    if let openSection = openSection, openSection != indexpath.section {
       section[openSection].isOpened = false
       section[indexPath.section].isOpened = true
       tableView.reloadSections([ openSection, indexPath.section], with: .automatic)
       openSection = indexPath.section
    } else {
      sections[indexPath.section].isOpened.toggle()
      tableView.reloadSections([indexPath.section], with: .automatic)
      openSection = sections[indexPath.section].isOpened ? indexPath.section : nil
    }
}

TableView 在 Swift 中展开和折叠单元格

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