用C ++中的普通元音替换重音元音

Question

我有一个带有西班牙语文本的字符串，我想像这样替换某些字符：

character	replace-with:
á	a
é	e
í	i
ó	o
ú	u
ñ	n

我试过了，没有结果：

std::string RemoverTildes(std::string str){
    std::string sinTildes = str.c_str();
    for(int i = 0; i < str.length(); i++){
        if(sinTildes[i] == 'á'){
            sinTildes[i] = 'a';
        } else if(sinTildes[i] == 'é'){
            sinTildes[i] = 'e';
        } else if(sinTildes[i] == 'í'){
            sinTildes[i] = 'i';
        } else if(sinTildes[i] == 'ó'){
            sinTildes[i] = 'o';
        } else if(sinTildes[i] == 'ú'){
            sinTildes[i] = 'u';
        } else if(sinTildes[i] == 'ñ'){
            sinTildes[i] = 'n';
        }
    }
    return sinTildes;
}

我怎样才能做到这一点？有没有我可以用来做这件事的图书馆或其他东西？

Answer 1

您可以使用 Unicode (UTF-16LE) wchar_t 来操作此字符。您可以阅读有关 char 类型 here.

的更多信息

这是您的代码和使用示例。

#include <iostream>

void tildesRemover(wchar_t* wideString) {
  auto stringLen = sizeof(wideString);
  for (int i = 0; i < stringLen; i++){
    if (wideString[i] == L'á'){
      wideString[i] = 'a';
    } else if (wideString[i] == L'é'){
      wideString[i] = 'e';
    } else if (wideString[i] == L'í'){
      wideString[i] = 'i';
    } else if (wideString[i] == L'ó'){
      wideString[i] = 'o';
    } else if (wideString[i] == L'ú'){
      wideString[i] = 'u';
    } else if (wideString[i] == L'ñ'){
      wideString[i] = 'n';
    }
  }
}

int main() {
  wchar_t wideString[] = L"áíéíúñó";

  tildesRemover(wideString);

  std::wcout << wideString << std::endl;

  return 0;
}

L这里指定wchar_t.

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