(mysql) 我怎样才能得到总和?
(mysql) how can i get sum of sum?
(select sum(serreq_totalamount)
from servicerequirement
group by key_id)+
(select sum(facreq_totalamount)
from facilityrequirement
group by key_id)+
(select sum(resorder_totalamount)
from restaurantorder
group by key_id)
我想得到总和。如我所愿。
如何创建一个将这三个表的总和列相加的列?
首先3太难了,我试了2个表,但是报错
select (
(select sum(serreq_totalamount)
from servicerequirement
group by servicerequirement.key_id)+
(select sum(facreq_totalamount)
from facilityrequirement
group by facilityrequirement.key_id));
Error Code: 1242. Subquery returns more than 1 row 0.000 sec
加入也是如此。
(select
(select sum(serreq_totalamount)
from servicerequirement
group by servicerequirement.key_id),
(select sum(facreq_totalamount)
from facilityrequirement
group by facilityrequirement.key_id)
from servicerequirement
inner join facilityrequirement
on servicerequirement.key_id=facilityrequirement.key_id);
Error Code: 1242. Subquery returns more than 1 row 0.000 sec
如果有人帮助我,我会很高兴。
您必须在 key_id
之前提出申请并加入他们
然后你可以把它们加起来
SELECT t1.key_id,s1+s2+s3
FROM
(select key_id,sum(serreq_totalamount) s1
from servicerequirement
group by key_id) t1
INNER JOIN
(select key_id,sum(facreq_totalamount) s2
from facilityrequirement
group by key_id) t2 ON t1.key_id = t2.key_id
INNER JOIN
(select key_id,sum(resorder_totalamount)
from restaurantorder
group by key_id) t3 ON t2.key_id = t3.key_id
(select sum(serreq_totalamount)
from servicerequirement
group by key_id)+
(select sum(facreq_totalamount)
from facilityrequirement
group by key_id)+
(select sum(resorder_totalamount)
from restaurantorder
group by key_id)
我想得到总和。如我所愿。
如何创建一个将这三个表的总和列相加的列?
首先3太难了,我试了2个表,但是报错
select (
(select sum(serreq_totalamount)
from servicerequirement
group by servicerequirement.key_id)+
(select sum(facreq_totalamount)
from facilityrequirement
group by facilityrequirement.key_id));
Error Code: 1242. Subquery returns more than 1 row 0.000 sec
加入也是如此。
(select
(select sum(serreq_totalamount)
from servicerequirement
group by servicerequirement.key_id),
(select sum(facreq_totalamount)
from facilityrequirement
group by facilityrequirement.key_id)
from servicerequirement
inner join facilityrequirement
on servicerequirement.key_id=facilityrequirement.key_id);
Error Code: 1242. Subquery returns more than 1 row 0.000 sec
如果有人帮助我,我会很高兴。
您必须在 key_id
之前提出申请并加入他们然后你可以把它们加起来
SELECT t1.key_id,s1+s2+s3
FROM
(select key_id,sum(serreq_totalamount) s1
from servicerequirement
group by key_id) t1
INNER JOIN
(select key_id,sum(facreq_totalamount) s2
from facilityrequirement
group by key_id) t2 ON t1.key_id = t2.key_id
INNER JOIN
(select key_id,sum(resorder_totalamount)
from restaurantorder
group by key_id) t3 ON t2.key_id = t3.key_id