如何传递 "select level from dual connect by level < " 中的行数？

Question

我有一个 table 包含一些随机自然数，例如：

number
-------
2
3
1

我想从这个 table 中检索一个集合，其中每一行将包含与值显示的次数一样多的次数，例如上面它将是：

number
-------
2
2
3
3
3
1

我正在考虑这样的查询：

select t.number from table t, (select level from dual connect by level <= t.number)

但显然它不起作用。

如何解决？

Answer 1

试试这个方法：

select t.id 
from tab t
join (SELECT ROWNUM as id
FROM ALL_OBJECTS
WHERE ROWNUM<=(select max(id) from tab)) t2 on t2.id <= t.id;

我不确定这个查询的性能如何，但结果符合预期。

Sql fiddle Demo

Answer 2

这是对 Oracle 数据库的查询：

SELECT t1.number 
FROM t t1
JOIN (SELECT LEVEL FROM dual CONNECT BY LEVEL<=(SELECT MAX(number) FROM t)) t2 
ON t2.level<= t1.number;

Answer 3

我是 MS-SQL:

declare @str nvarchar(max);
set @str = 'select * from table where number = 0 ';
declare @c2 int;
declare @c3 int;
with cte as (select row_number() over (order by number) as seq,number from table)   
select  @c2 = max(seq) from cte;
declare @c1 int = 1;
declare @c4 int = 1;
select @c3 = min(number) from table
while (@c1 <= @c2)
begin
while (@c4 <= @c3)
begin
set @str += ' union all select * from table where number = ' + cast (@c3 as nvarchar)
set @c4 += 1
end
set @c1 += 1;
select @c3 = number from table where number = @c3 + 1
set @c4 = 1
end
set @str += ' order by number'
execute(@str)

如何传递 "select level from dual connect by level < " 中的行数？

How to pass number of lines in "select level from dual connect by level < "?

sql

database

oracle