async 关键字无法使用节点 js 处理函数

Question

我不知道为什么会出现此错误

uncaughtException: await 仅在异步函数中有效

因为我在 getChild 函数中使用 async 关键字，我仍然收到此错误

我的代码：

async function filterFile(folderPath) {
  try {
    wantExt = [".jpg"];
    let parts;
    const paths = await checkFileLoc(folderPath, 3);
    const otherFiles = [];

    for (const filePath of paths) {
      parts = filePath.split("/");
      let splitFileName = parts[parts.length - 1].split(".");
      if (wantExt.includes(`.${splitFileName[splitFileName.length - 1]}`)) {
        otherFiles.push(filePath);
      }
    }
    let ignoreFile = otherFiles.filter((x) =>
      x.endsWith("_bio.jpg")
    );
    let test = otherFiles.filter((x) => !ignoreZipFile.includes(x));
    return { test };
  } catch (error) {
    console.log("error:", error);
  }
}

async function getChild(parents) {
  return new Promise(function (resolve, reject) {
    Shop.findAll({
      where: {
        shop_no: parents.id,
      },
      attributes: ["id", "name"],
    })
      .then((children) => {

        let gotValue= await filterFile(children);
        console.log(gotValue);

        resolve(children);
      })
      .catch(function (err) {
        reject(err);
      });
  });
}

如果我从函数中删除 async 那么我会得到 gotValue 因为 promise 不知道如何获取值

Answer 1

async function filterFile(folderPath) {
  try {
    wantExt = [".jpg"];
    let parts;
    const paths = await checkFileLoc(folderPath, 3);
    const otherFiles = [];

    for (const filePath of paths) {
      parts = filePath.split("/");
      let splitFileName = parts[parts.length - 1].split(".");
      if (wantExt.includes(`.${splitFileName[splitFileName.length - 1]}`)) {
        otherFiles.push(filePath);
      }
    }
    let ignoreFile = otherFiles.filter((x) =>
      x.endsWith("_bio.jpg")
    );
    let test = otherFiles.filter((x) => !ignoreZipFile.includes(x));
    return { test };
  } catch (error) {
    console.log("error:", error);
  }
}

async function getChild(parents) {
  try {
    const children = await Shop.findAll({
      where: {
        shop_no: parents.id,
      },
      attributes: ["id", "name"],
    });
    let gotValue= await filterFile(children);
    console.log(gotValue);
    return children;
  } catch(err) {
    throw(err);
  }
}

Answer 2

尝试向 findAll 中的回调函数添加异步

async function getChild(parents) {
  return new Promise(function (resolve, reject) {
    Shop.findAll({
      where: {
        shop_no: parents.id,
      },
      attributes: ["id", "name"],
    })
      .then(async (children) => { // Add it here

        let gotValue= await filterFile(children);
        console.log(gotValue);

        resolve(children);
      })
      .catch(function (err) {
        reject(err);
      });
  });
}

Answer 3

您之前错过了 async 个关键字

(children) => {
     let gotValue = await filterFile(children);
     console.log(gotValue);
     resolve(children);
}

函数。应该是

async (children) => {
     let gotValue = await filterFile(children);
     console.log(gotValue);
     resolve(children);
}

Answer 4

“await 仅在异步函数中有效” 正如错误所说，在异步函数中使用了 await。

const fn = async () => { await someAsyncFunction() };

所以在你的场景中，让回调异步以及等待 filterFile 代码。

.then(async (children) => {
    let gotValue= await filterFile(children);
    console.log(gotValue);

    resolve(children);
 })

async 关键字无法使用节点 js 处理函数

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