Firebase

Question

假设我的 Firebase 上有以下数据：

https://mygame.firebaseio.com/player

{
  "player": {
    "bloodgulf01": {
      "username": "bloodgulf01",
      "uid": "twitter:102032",
      "level": 2,
      "map": 3,
      "x": 51,
      "y": 12
    },
    "damjanovic": {
      "username": "damjanovic",
      "uid": "github:77371",
      "level": 5,
      "map": 2,
      "x": 21,
      "y": 44
    }
  }
}

我如何按 uid 进行搜索并获得结果 snapshot？

这是我尝试过的：

new Firebase("https://mygame.firebaseio.com/player")
    .startAt(authData.uid)
    .endAt(authData.uid)
    .once('value', function(snap) {
       console.log('accounts matching UID of ' + authData.uid, snap.val())
    });

returns：accounts matching UID of github:123456789 null 尽管在 /player/ 的数据中有 uid...

Answer 1

记住，Firebase 中的一切都是 url。所以你可以这样做来获得你想要的数据：

'https://mygame.firebaseio.com/player/' + uid

Answer 2

按要筛选的 child 排序，然后筛选：

new Firebase("https://mygame.firebaseio.com/player")
  .orderByChild('uid')
  .equalTo(authData.uid)
  .once('child_added', function(snap) {
     console.log('account matching UID of ' + authData.uid, snap.val())
  });

由于您只需要一个玩家，因此 once('child_added' 或许可以应付。如果您需要处理具有相同 uid 的潜在多个玩家，则：

  .on('child_added', function(snap) {
     console.log('account matching UID of ' + authData.uid, snap.val())
  });

或

  .once('value', function(snap) {
     snap.forEach(function(child) {
       console.log('account matching UID of ' + authData.uid, child.val())
     });
  });

虽然我在结构上支持 Chrillewoodz：我总是希望看到 uid 作为用户集合的键。那你可以用上面的方法搜索名字。

Firebase - 按值搜索 child

Firebase - Search a child by value

javascript

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