将 CSS 背景图像 属性 转换为 LESS css

convert CSS background-image property in to LESS css

如何将以下 CSS3 转换为 LESS Mixin。谁能帮忙解决这个问题。

.progress-striped {
    background-image: -moz-linear-gradient(45deg, rgba(255, 255, 255, 0.15) 25%, transparent 25%, transparent 50%, rgba(255, 255, 255, 0.15) 50%, rgba(255, 255, 255, 0.15) 75%, transparent 75%, transparent);
    background-image: -webkit-gradient(linear, 0 100%, 100% 0, color-stop(0.25, rgba(255, 255, 255, 0.15)), color-stop(0.25, transparent), color-stop(0.5, transparent), color-stop(0.5, rgba(255, 255, 255, 0.15)), color-stop(0.75, rgba(255, 255, 255, 0.15)), color-stop(0.75, transparent), to(transparent));
    background-image: -webkit-linear-gradient(45deg, rgba(255, 255, 255, 0.15) 25%, transparent 25%, transparent 50%, rgba(255, 255, 255, 0.15) 50%, rgba(255, 255, 255, 0.15) 75%, transparent 75%, transparent);
    background-image: linear-gradient(45deg, rgba(255, 255, 255, 0.15) 25%, transparent 25%, transparent 50%, rgba(255, 255, 255, 0.15) 50%, rgba(255, 255, 255, 0.15) 75%, transparent 75%, transparent);
}

你想用这样的东西吗?

@mixin linear-gradient($direction, $color-stops...) {
  background: nth(nth($color-stops, 1), 1);
  background: -webkit-linear-gradient(legacy-direction($direction), $color-stops);
  background: linear-gradient($direction, $color-stops);
}

参考Building a Linear-gradient Mixin in Sass了解更多信息。 Sass 和 LESS 在 mixins 中几乎是一样的。

完整的 mixin 是:

/// Mixin printing a linear-gradient
/// as well as a plain color fallback
/// and the `-webkit-` prefixed declaration
/// @access public
/// @param {Keyword | Angle} $direction - Linear gradient direction
/// @param {Arglist} $color-stops - List of color-stops composing the gradient
@mixin linear-gradient($direction, $color-stops...) {
  background: nth(nth($color-stops, 1), 1);
  background: -webkit-linear-gradient(legacy-direction($direction), $color-stops);
  background: linear-gradient($direction, $color-stops);
}

用法是:

@include linear-gradient(hotpink, tomato);