如何从 Typescript 中的对象内联解构嵌套的可选属性？

Question

我有以下 User 类型的代码，它具有可选类型 Address，我想在一行中对其进行解构。但是，当我尝试时，我收到一条错误消息：

Property 'street' does not exist on type 'Address | undefined'

Click here to see the Typescript playground of the code provided bellow

type User = {
 age: number;
 address?: Address;
}

type Address = {
 street?: string;
}

const user: User = {
 age: 22,
 address: {}
}

const {age, address: {street}} = user

此处 街道 在类型 Address | undefined

上不存在

Answer 1

您需要在 const 中初始化 address。

像这样：

const {age, address : {street} = {}} = user;

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