我在 mysql 中的触发器错误，请帮助修复

Question

我不明白为什么我的触发器不起作用。

第一table:

CREATE TABLE `Payment` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `idPaymentMethod` int(20) DEFAULT NULL,
  `createAt` timestamp NOT NULL DEFAULT current_timestamp(),
  `updateAt` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00' ON UPDATE current_timestamp(),
  `actived` tinyint(1) NOT NULL DEFAULT 1,
  `numberInvoices` int(11) DEFAULT NULL,
  `preferentialPaymentDay` int(11) DEFAULT NULL,
  `invoicesFrequency` bigint(20) NOT NULL DEFAULT 0,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=6 DEFAULT CHARSET=utf8;

秒table:

CREATE TABLE `PaymentHistory` (
  `id` bigint(20) NOT NULL AUTO_INCREMENT,
  `idPaymentMethod` int(20) DEFAULT NULL,
  `idPayment` int(20) DEFAULT NULL,
  `createAt` timestamp NOT NULL DEFAULT current_timestamp(),
  `updateAt` timestamp NOT NULL DEFAULT '0000-00-00 00:00:00' ON UPDATE current_timestamp(),
  `actived` tinyint(1) NOT NULL DEFAULT 1,
  `numberInvoices` int(11) DEFAULT NULL,
  `preferentialPaymentDay` int(11) DEFAULT NULL,
  `invoicesFrequency` bigint(20) NOT NULL DEFAULT 0,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM AUTO_INCREMENT=6 DEFAULT CHARSET=utf8;

我的触发器：

DELIMITER $$
CREATE
TRIGGER `update_history` AFTER
UPDATE
    ON
    `Payment` 
FOR EACH ROW BEGIN

    UPDATE
    `PaymentHistory`
SET
    id = OLD.id,
    idPaymentMethod = old.idPaymentMethod,
    createAt = old.createAt,
    updateAt = old.updateAt,
    actived = old.actived,
    numberInvoices = old.numberInvoices

END$$

当我尝试修复某些东西时遇到很多错误。

我得到的错误：

SQL 错误 [1064] [42000]：您的 SQL 语法有误；查看与您的 MariaDB 服务器版本对应的手册，了解在第 1

行 'END$$' 附近使用的正确语法

SQL 错误 [1054] [42S22]：'field list'

中的未知列 'OLD.id'

我真的迷路了

我需要将“付款”中的所有更新数据table插入或更新到“PaymentHistory”table

拜托，我需要帮助。

Answer 1

你需要用分号结束每个命令

DELIMITER $$
CREATE
TRIGGER `update_history` AFTER
UPDATE
    ON
    `Payment` 
FOR EACH ROW BEGIN

    UPDATE
    `PaymentHistory`
SET
    id = OLD.id,
    idPaymentMethod = old.idPaymentMethod,
    createAt = old.createAt,
    updateAt = old.updateAt,
    actived = old.actived,
    numberInvoices = old.numberInvoices;

END$$

DELIMITER ;

见example

Answer 2

首先感谢@nbk

我在你的帮助下解决了

我将“之后”更改为“之前”并添加“；”

见；

TRIGGER `update_history` BEFORE
UPDATE
    ON
    `Payment` 
FOR EACH ROW BEGIN

    UPDATE
    `PaymentHistory`
SET
     idPayment = old.id
    , idPaymentMethod = old.idPaymentMethod
    , createAt = old.createAt
    , updateAt = old.updateAt
    , actived = old.actived
    , numberInvoices = old.numberInvoices;

END

我在 mysql 中的触发器错误，请帮助修复

my trigger error in mysql, hen help to fix

mysql

sql

triggers