在 python 中制作一个 4x4 数组

Question

我正在尝试创建一个看起来像这样的 4x4 数组：This is a javascript code that I'm trying to create into python

[0, 1, 2, 3]

[4、5、6、7]

[8, 9, 10, 11]

[12, 13, 14, 15]

    height = 4
    width = 4

    num = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

    for i in range(0, height * width, 4):
        row = []
        for j in range(i, i + width, 1):
            row.append(num[j])
            print(row)

Answer 1

如果您正在寻找替代建议，我建议您使用 numpy:

import numpy as np

height, width = 4, 4
num = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]

array = np.array(num).reshape((height, width))
print(array)

输出：

array([[ 0,  1,  2,  3],
       [ 4,  5,  6,  7],
       [ 8,  9, 10, 11],
       [12, 13, 14, 15]])

Answer 2

看看这个：

num = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
def check(num,each=4):
    for i in range(0,num,each):
        print(num[i:i+4])
check(16,4)

Answer 3

有点小错误...！

height = 4
width = 4
num = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15]
for i in range(0, height*width, 4):
    row = []
    for j in range(i, i+width):
        row.append(num[j])
    print(row) # this statement should be outside the second for loop

在 python 中制作一个 4x4 数组

Making a 4x4 array in python

python

arrays

for-loop

append