C++ 比较彩票游戏中的数组值

Question

我正在制作一个彩票程序，我正在尝试制作一个函数来检查有多少用户的号码与中奖号码相同，并写出具有相同号码的不同奖励。代码编译得很好。我只是遇到创建函数以及在其中做什么的问题。

基本上，检查他们是否赢得了乐透游戏中的任何奖品。检查 UserTicket 数组中的每个数字以查看该数字是否在 WinningNums 数组中并计算匹配的数字。

显示：JACKPOT - 如果所有 7 个号码都正确，则为 100 万显示：太棒了！ - 100,000 美元，如果 6 个数字是正确的显示：幸运的你！ - 5,000 美元，如果 5 个数字是正确的显示：不错 - 如果 4 个号码正确，则 100 美元显示：FREE TICKET if 3 numbers are correct 显示：如果 2 个或更少的数字是正确的，则没有任何意义

我在这方面遇到了麻烦，我是 C++ 的新手，而且我只编写了几个月的代码。将不胜感激！

#include <iostream>
#include <ctime>
#include <cstdlib>
#include <string>

using namespace std;

void getLottoPicks(int userNums[], int size);
void genWinNums(int winNums[], int size);
void checkNums(int userNums[], int winNums[], int size);

int main()
{
    const int size = 7;
    int UserTicket[size];
    int WinningNums[size];
    char selection;
    string name;

    do
    {
        cout << "LITTLETON CITY LOTTO MODEL: " << endl;
        cout << "---------------------------" << endl;
        cout << "1) Play Lotto" << endl;
        cout << "q) Quit Program" << endl;
        cout << "Please make a selection : " << endl;
        cin >> selection;

        if (selection == '1')
        {
            cout << "Please enter your name: " << endl;
            cin.ignore();
            getline(cin, name);

            getLottoPicks(UserTicket, size);
            genWinNums(WinningNums, size);
            checkNums(int userNums[], int winNums[], int size);

            cout << name << "'s LOTTO RESULTS" << endl;
            cout << "----------------------" << endl;
            cout << "WINNING TICKET NUMBERS : " << endl;
            for(int i = 0; i < size; i++)
            {
            cout << WinningNums[i] << " ";
            }
            cout << endl;
            cout << name << "'s TICKET       : " << endl;
            for(int i = 0; i < size; i++)
            {
                cout << UserTicket[i] << " ";
            }
            cout << endl;

        }
        else if (selection == 'q')
        {
            cout << "You have chosen to quit the program. Thank you for 
            using!" << endl;
        }
        else
        {
            cout << "Invalid selection. Please try again." << endl;
        }

    } while (selection != 'q');

    return 0;
}
void getLottoPicks(int userNums[], int size)
{
    for (int times = 0; times < size; times++)
    {
        int input;
        cout << "selection #" << times + 1 << ": " << endl;
        cin >> input;

        bool isNotDuplicate = true;
        for (int i = 0; i < times; i++)
        {
            if (userNums[i] == input)
            {
                 isNotDuplicate = false;
            }
        }
        if (isNotDuplicate == true)
        {
             userNums[times] = input;
        }
        else
        {
             cout << "You already picked this number. Please enter a different number: " <<
             endl;
             times--;
        }
     }

}
void genWinNums(int winNums[], int size)
{
    srand((unsigned int)time(NULL));

    for (int times = 0; times < size; times++)
    {
        int i;
        bool isNotDuplicate = true;
        while (isNotDuplicate)
        {
            isNotDuplicate = false;
            i = 1 + rand() % 40;
            for (int j = 0; j < times; j++)
            {
                if (i == winNums[j])
                {
                    isNotDuplicate = true;
                }
            }  
        }
        winNums[times] = i;
    }
}
void checkNums(int userNums[], int winNums[], int size)
{

}

Answer 1

你应该做 2 个循环，像这样：

int checkNums(int userNums[], int winNums[], int size)
{
    int nums = 0;

    for(int i = 0; i < size; i++)
        for(int j = 0; j < size; j++)
            if(userNums[i] == winNums[j])
                nums++;
     
    return nums;
}

这个函数会return有多少个数字是正确的如果您不关心顺序并且您确定没有数字可以在同一个数组中出现 2 次，则此方法有效。如果您也想查看订单：

int checkNums(int userNums[], int winNums[], int size)
{
    int nums = 0;

    for(int i = 0; i < size; i++)
        if(userNums[i] == winNums[i])
            nums++;
     
    return nums;
}

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