根据日期范围 sql 添加值

Question

卡在下面的问题上。

Current data: table1

|emp_id | date     | day_one |week_num |
 --------------------------------------
|    100|2021-01-01|     TRUE|        1|
|    100|2021-01-02|     NULL|     NULL|
|    100|2021-01-03|     NULL|     NULL|
|    100|2021-01-04|     NULL|     NULL|
|    100|2021-01-05|     NULL|     NULL|
|    100|2021-01-06|     NULL|     NULL|
|    100|2021-01-07|     NULL|     NULL|
|    100|2021-01-08|     NULL|     NULL|
|    100|2021-01-09|     NULL|     NULL|
|    100|2021-01-10|     NULL|     NULL|
|    100|2021-01-11|     NULL|     NULL|
|    100|2021-01-12|     NULL|     NULL|
|    100|2021-01-13|     NULL|     NULL|
|    100|2021-01-14|     NULL|     NULL|
 --------------------------------------

期望的输出：

|emp_id | dates    | day_one |week_num |
 --------------------------------------
|    100|2021-01-01|     TRUE|        1|
|    100|2021-01-02|     NULL|        1|
|    100|2021-01-03|     NULL|        1|
|    100|2021-01-04|     NULL|        1|
|    100|2021-01-05|     NULL|        1|
|    100|2021-01-06|     NULL|        1|
|    100|2021-01-07|     NULL|        1|
|    100|2021-01-08|     NULL|        2|
|    100|2021-01-09|     NULL|        2|
|    100|2021-01-10|     NULL|        2|
|    100|2021-01-11|     NULL|        2|
|    100|2021-01-12|     NULL|        2|
|    100|2021-01-13|     NULL|        2|
|    100|2021-01-14|     NULL|        2|
 --------------------------------------

数据中有许多员工跨越数千个日期，因此需要以基于 day_one 列添加周数的方式来完成。我使用了 lag/lead，但如果员工的工作周期为 8 周，它就会变得非常低效。下面的代码给出 week_num =1，重复给出 2 等

with t1 as (
select 
    *
    ,
    LAG(week_num) OVER(PARTITION BY emp_id ORDER BY emp_id, dates) as second_day,
    LAG(week_num, 2) OVER(PARTITION BY emp_id ORDER BY emp_id, dates) as third_day,
    LAG(week_num, 3) OVER(PARTITION BY emp_id ORDER BY emp_id, dates) as forth_day,
    LAG(week_num, 4) OVER(PARTITION BY emp_id ORDER BY emp_id, dates) as fifth_day,
    LAG(week_num, 5) OVER(PARTITION BY emp_id ORDER BY emp_id, dates) as sixth_day,
    LAG(week_num, 6) OVER(PARTITION BY emp_id ORDER BY emp_id, dates) as seventh_day
from table1 
)
select 
    emp_id,
    dates,
    day_one,
    case when week_num = 1 then 1 
         when second_day = 1 then 1 
         when third_day = 1 then 1 
         when forth_day = 1 then 1 
         when fifth_day = 1 then 1 
         when sixth_day = 1 then 1 
         when seventh_day = 1 then 1 
         else NULL 
    end as week_num
from table1
order by emp_id, dates

问题的第 2 级。当前数据：

|emp_id | dates    | day_one |week_num |
 --------------------------------------
|    100|2021-01-01|     TRUE|        1|
|    100|2021-01-02|     NULL|     NULL|
|    100|2021-01-03|     NULL|     NULL|
|    100|2021-01-04|     NULL|     NULL|
|    100|2021-01-05|     NULL|     NULL|
|    100|2021-01-06|     NULL|     NULL|
|    100|2021-01-07|     NULL|     NULL|
|    100|2021-01-08|     NULL|     NULL|
|    100|2021-01-09|     NULL|     NULL|
|    100|2021-01-10|     NULL|     NULL|
|    100|2021-01-11|     NULL|     NULL|
|    100|2021-01-12|     NULL|     NULL|
|    100|2021-01-13|     NULL|     NULL|
|    100|2021-01-14|     NULL|     NULL|
|    100|2021-01-15|     NULL|     NULL|
|    100|2021-01-16|     NULL|     NULL|
|    100|2021-01-17|     NULL|     NULL|
|    100|2021-01-18|     NULL|     NULL|
|    100|2021-01-19|     NULL|     NULL|
|    100|2021-01-20|     NULL|     NULL|
|    100|2021-01-21|     NULL|     NULL|
|    100|2021-01-22|     NULL|     NULL|
|    100|2021-01-23|     NULL|     NULL|
|    100|2021-01-24|     NULL|     NULL|
|    100|2021-01-25|     NULL|     NULL|
|    100|2021-01-26|     NULL|     NULL|
|    100|2021-01-27|     NULL|     NULL|
|    100|2021-01-28|     NULL|     NULL|
 --------------------------------------

期望的输出（重复周期）：

|emp_id | dates    | day_one |week_num |
 --------------------------------------
|    100|2021-01-01|     TRUE|        1|
|    100|2021-01-02|     NULL|        1|
|    100|2021-01-03|     NULL|        1|
|    100|2021-01-04|     NULL|        1|
|    100|2021-01-05|     NULL|        1|
|    100|2021-01-06|     NULL|        1|
|    100|2021-01-07|     NULL|        1|
|    100|2021-01-08|     NULL|        2|
|    100|2021-01-09|     NULL|        2|
|    100|2021-01-10|     NULL|        2|
|    100|2021-01-11|     NULL|        2|
|    100|2021-01-12|     NULL|        2|
|    100|2021-01-13|     NULL|        2|
|    100|2021-01-14|     NULL|        2|
|    100|2021-01-15|     NULL|        1|
|    100|2021-01-16|     NULL|        1|
|    100|2021-01-17|     NULL|        1|
|    100|2021-01-18|     NULL|        1|
|    100|2021-01-19|     NULL|        1|
|    100|2021-01-20|     NULL|        1|
|    100|2021-01-21|     NULL|        1|
|    100|2021-01-22|     NULL|        2|
|    100|2021-01-23|     NULL|        2|
|    100|2021-01-24|     NULL|        2|
|    100|2021-01-25|     NULL|        2|
|    100|2021-01-26|     NULL|        2|
|    100|2021-01-27|     NULL|        2|
|    100|2021-01-28|     NULL|        2|
 --------------------------------------

Answer 1

如果日期和每周 7 天没有间隔

select 
    emp_id,
    dates,
    day_one,
    datediff(day,
         (select top(1) dates 
          from table1 t2
          where t2.emp_id = t1.emp_id and t2.day_one='TRUE'
          order by t2.dates),
         dates) % 7 + 1  
from table1 t;

Answer 2

-- PLEASE PROVIDE SET UP SCRIPT FOR SAMPLE DATA IN FUTURE POSTS

CREATE TABLE #table1
(
   emp_id   INT
  ,dates    DATE 
  ,day_one  VARCHAR(9)
  ,week_num_expected INT
);

INSERT INTO #table1(emp_id,dates,day_one,week_num_expected) VALUES
 (100,'2021-01-01','TRUE',1),(100,'2021-01-02',NULL,1),(100,'2021-01-03',NULL,1),(100,'2021-01-04',NULL,1)
,(100,'2021-01-05',NULL,1),(100,'2021-01-06',NULL,1),(100,'2021-01-07',NULL,1),(100,'2021-01-08',NULL,2)
,(100,'2021-01-09',NULL,2),(100,'2021-01-10',NULL,2),(100,'2021-01-11',NULL,2),(100,'2021-01-12',NULL,2)
,(100,'2021-01-13',NULL,2),(100,'2021-01-14',NULL,2),(100,'2021-01-15',NULL,1),(100,'2021-01-16',NULL,1)
,(100,'2021-01-17',NULL,1),(100,'2021-01-18',NULL,1),(100,'2021-01-19',NULL,1),(100,'2021-01-20',NULL,1)
,(100,'2021-01-21',NULL,1),(100,'2021-01-22',NULL,2),(100,'2021-01-23',NULL,2),(100,'2021-01-24',NULL,2)
,(100,'2021-01-25',NULL,2),(100,'2021-01-26',NULL,2),(100,'2021-01-27',NULL,2),(100,'2021-01-28',NULL,2);


-- MAYBE ??
SELECT
  emp_id,
  dates,
  day_one,
  week_num_expected,
  CASE
    WHEN (ROW_NUMBER() OVER (ORDER BY dates ASC) - 1) / 7 = 0
    OR
    ((ROW_NUMBER() OVER (ORDER BY dates ASC) - 1) / 7) % 2 = 0 
    THEN 1
    ELSE 2
  END AS week_num_by_code

FROM #table1

DROP TABLE #table1

根据日期范围 sql 添加值

adding values based on date range sql

sql

sql-server

date-range