CodeIgniter

Question

目前我可以在 CodeIgniter 中做如下 WHERE 语句：

$builder = $db->table('mytable');
$builder->select(*);
$builder->where('age >='.$params['some-param']);

我需要做的是一个仅在 IF 语句为真时才适用的 WHERE 语句。类似于：

(IF gender = 'Male', apply these rows the following where) $builder->where('age >='.$params['some-param']);
(IF gender = 'Female', apply these other rows, this where and not the first one) $builder->where('age >='.$params['some-other-param']);

另请注意，['some-param'] 和 ['some-other-param'] 并不总是存在。我知道它可以用 OR 语句来实现，但是如果 ['some-other-param'] 没有设置，那么查询将是这样的：

$builder->where("age >=".$params['some-param']." AND gender = 'Male'");

而且这不会包括任何性别 = 'Female' 的行，我也需要它。

我不知道如何做到这一点。任何方向将不胜感激。

Answer 1

这样的东西行不通吗？

-- Both age filters are set
select *
from my_table
where (
    (gender = 'Male' and age >= 20)
    or 
    (gender = 'Female' and age >= 30)
)

-- Only Male filter is set
select *
from my_table
where (
    (gender = 'Male' and age >= 20)
    or 
    gender = 'Female'
)

-- Only Female filter is set
select *
from my_table
where (
    (gender = 'Female' and age >= 20)
    or 
    gender = 'Male'
)

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