Pyspark：爆炸阵列慢

Question

我的数据框

df_a = spark.createDataFrame( [ 
                               (0, ["B","C","D","E"] , [1,2,3,4] ),
                               (1,["E","A","C"] , [1,2,3] ),
                               (2, ["F","A","E","B"] , [1,2,3,4]),
                               (3,["E","G","A"] , [1,2,3 ]),
                               (4,["A","C","E","B","D"] , [1,2,3,4,5])] , ["id","items",'rank'])

我希望输出为：

+---+----+----+
| id|item|rank|
+---+----+----+
|  0|   B|   1|
|  0|   C|   2|
|  0|   D|   3|
|  0|   E|   4|
|  1|   E|   1|
|  1|   A|   2|
|  1|   C|   3|
|  2|   F|   1|
|  2|   A|   2|
|  2|   E|   3|
|  2|   B|   4|
|  3|   E|   1|
|  3|   G|   2|
|  3|   A|   3|
|  4|   A|   1|
|  4|   C|   2|
|  4|   E|   3|
|  4|   B|   4|
|  4|   D|   5|
+---+----+----+

我的数据框有 800 万行，当我尝试如下所示压缩和分解时，它非常慢，并且使用 15 个执行程序和 25GB 内存永远运行作业

zip_udf2 = F.udf(
    lambda x, y: list(zip(x, y)),
    ArrayType(StructType([
        StructField("item", StringType()),
        StructField("rank", IntegerType())
        
    ]))
)

(df_a
 .withColumn('tmp', zip_udf2("items", "rank"))
 .withColumn("tmp", F.explode('tmp'))
 .select("id", F.col("tmp.item"), F.col("tmp.rank"))
 .show())

还有其他方法吗？我试过 rdd.flatMap 仍然没有对性能产生影响。 每一行中数组中的元素数量各不相同。

Answer 1

更新

由于您使用的是 Spark 2.3.2 并且 arrays_zip 不可用，我做了一些测试来比较哪个是最好的选择：udf 或 posexplode。快速回答是：posexplode.

(df_a
 .select('id', F.posexplode('items'), 'rank')
 .select('id', F.col('col').alias('item'), F.expr('rank[pos]').alias('rank'))
 .show())

测试

from pyspark.sql.types import *

import pyspark.sql.functions as F
import time


df_a = spark.createDataFrame([ 
  (0, ["B","C","D","E"] , [1,2,3,4] ),
  (1,["E","A","C"] , [1,2,3] ),
  (2, ["F","A","E","B"] , [1,2,3,4]),
  (3,["E","G","A"] , [1,2,3 ]),
  (4,["A","C","E","B","D"] , [1,2,3,4,5])] , ["id","items",'rank'])


# My solution
def using_posexplode():
  (df_a
   .select('id', F.posexplode('items'), 'rank')
   .select('id', F.col('col').alias('item'), F.expr('rank[pos]').alias('rank'))
   .count())


# Your solution
zip_udf2 = F.udf(
  lambda x, y: list(zip(x, y)),
  ArrayType(StructType([
    StructField("item", StringType()),
    StructField("rank", IntegerType())
  ])))

def using_udf():
  (df_a
   .withColumn('tmp', zip_udf2("items", "rank"))
   .withColumn("tmp", F.explode('tmp'))
   .select("id", F.col("tmp.item"), F.col("tmp.rank"))
   .count())


def time_run_method(iterations, fn):
  t0 = time.time()
  for i in range(iterations):
    fn()
  td = time.time() - t0
  
  print(fn.__name__, "Time to count %d iterations: %s [sec]" % (iterations, "{:,}".format(td)))
  
for function in [using_posexplode, using_udf]:
  time_run_method(iterations=100, fn=function)

using_posexplode Time to count 100 iterations: 24.962905168533325 [sec]
using_udf Time to count 100 iterations: 44.120017290115356 [sec]

旧

不能保证只有这样才能解决您的整个问题，但需要考虑的一件事是删除您的 zip_udf2 并将其更改为 Spark 的本机函数 arrays_zip。 .

Pyspark：爆炸阵列慢

Pyspark: Explode array slow

python

explode

apache-spark-sql

pyspark

更新

测试

旧