如何使用 SQL 存储过程区分早晚班患者的性别

Question

我想按性别区分早上和晚上的病人登记人数，如果性别年龄小于则根据性别显示女童和男童。

SELECT 
    COUNT(ch.EnteredOn) AS counter, 
    CONVERT(date, ch.EnteredOn) AS sessionDay,
    SUM(CASE WHEN CAST(CONVERT(CHAR(2), ch.EnteredOn, 108) AS INT) < 12 THEN 1 ELSE 0 END) AS 'Morning',
    SUM(CASE WHEN CAST(CONVERT(CHAR(2), ch.EnteredOn, 108) AS INT) >= 12 THEN 1 ELSE 0 END) AS  'Evening',
    SUM(CASE WHEN p.Gender = 1 THEN 1 ELSE 0 END) AS Male,
    SUM(CASE WHEN p.Gender = 2 THEN 1 ELSE 0 END) AS Fmale,
    SUM(CASE WHEN DATEDIFF(hour, P.DOB, GETDATE()) / 8766 <= 18 
                  AND P.Gender = 1 THEN 1 ELSE 0 END) AS MChild,
    SUM(CASE WHEN DATEDIFF(hour, P.DOB, GETDATE()) / 8766 <= 18 
                  AND P.Gender = 2 THEN 1 ELSE 0 END) AS FChild
FROM 
    Patient.CheckIn ch
INNER JOIN
    Patient.Patients P ON ch.PatientId = p.PatientId
GROUP BY
    Ch.EnteredOn

我只有 Gender、Time 和 DOB 三列。 Gender id 1 表示男性，Gender id 2 表示女性。

enter image description here

Answer 1

SELECT convert(date, ch.EnteredOn) AS sessionDay, CAST( CONVERT(CHAR(2), ch.EnteredOn, 108) AS INT) <12 as morning, count(ch.EnteredOn) AS counter
,sum(case when p.Gender=1 Then 1 ELSE 0 end) as Male
,sum(case when p.Gender=2 Then 1 ELSE 0 end) as Fmale
,Sum( case when DATEDIFF(hour,P.DOB,GETDATE())/8766<=18 AND P.Gender=1 Then 1 ELSE 0 end ) as MChiled
,Sum( case when DATEDIFF(hour,P.DOB,GETDATE())/8766<=18 AND P.Gender=2 Then 1 ELSE 0 end ) as FChiled
FROM Patient.CheckIn ch
inner join Patient.Patients P on ch.PatientId=p.PatientId 
Group by Ch.EnteredOn

Group BY可以

Group by convert(date, ch.EnteredOn) AS sessionDay, CAST( CONVERT(CHAR(2), ch.EnteredOn, 108) AS INT) <12

如何使用 SQL 存储过程区分早晚班患者的性别

How can separate morning and evening shifts patients with gender wise using SQL stored procedure

database

sql-server

stored-procedures