等待多个任务

Awaiting Multiple Tasks

我有以下代码:

private async void buttonStart_ItemClick(object sender, DevExpress.XtraBars.ItemClickEventArgs e)
{
    Bot b = new Bot(_names);
    var result = await b.Start(false, true, false);
    MessageBox.Show("Done");
}

public async Task<bool> Start(bool instagram, bool twitter, bool xbox)
{
    if (twitter)
    {
        Twitter t = new Twitter(Names);
        await t.CheckNames();
    }
    return true;
}

public Task CheckNames()
{
    List<Task> tasks = new List<Task>();
    foreach (Name name in Names)
    {
        tasks.Add(Task.Factory.StartNew(async () =>
        {
            TwitterResponse result = await Check(name);
            MessageBox.Show(result.msg);
        }));
    }
    return Task.WhenAll(tasks);
}

public async Task<TwitterResponse> Check(Name name)
{
    HttpClient http = new HttpClient();
    HttpResponseMessage response = await http.GetAsync(string.Format("https://twitter.com/users/username_available?username={0}", name.Value));
    string html = response.Content.ReadAsStringAsync().Result;
    TwitterResponse result = new JavaScriptSerializer().Deserialize<TwitterResponse>(html);
    return result;
}

但是,我似乎总是在完成任何任务之前得到 MessageBox"Done"

我是不是做错了什么,我怎样才能确保在获得 messagebox 之前所有的任务都真正完成了?

问题是 tasks.Add(Task.Factory.StartNew(async () =>you should almost never be using Task.Factory.StartNew 行,而是使用 Task.Run(.

StartNew 返回的对象是一个 Task<Task>,这意味着它不等待内部任务完成。您必须在 StartNew 的输出上调用 .Unwrap(),然后再将其添加到集合中,或者更好地使用 Task.Run(

tasks.Add(Task.Run(async () =>
{
    TwitterResponse result = await Check(name);
    MessageBox.Show(result.msg);
}));

它有一个接受 Func<Task> 的重载,并会为您解包内部任务。