仅复制标签的值而不是排序时的所有标签

Question

我有 xml 需要按 2 个标签排序：Type 和 NonRecurringCharges。 Type标签的值不是唯一的（我的xml中有2个Product）。任何产品中都可能缺少 NonRecurringCharges 标签。我有一个 XLT 模板，但它排序和复制标签的值而不是标签。

希望有人能提供帮助。

XML:

<ContractSummary>
<OrderInfo>
    <IsMobileOnly>false</IsMobileOnly>
</OrderInfo>
<Offerings>
    <Type>Product</Type>
    <Name Language="NL">Cable Access</Name>
    <NonRecurringCharges>
        <Type>PostPaid</Type>
        <ThirdPartyFinancingId>CAAC0001</ThirdPartyFinancingId>
    </NonRecurringCharges>
</Offerings>
    <Offerings>
    <Type>OneTimeService</Type>
    <Name Language="NL">Cable Access</Name>
    <NonRecurringCharges>
        <Type>PostPaid</Type>
        <ThirdPartyFinancingId>CAAC0001</ThirdPartyFinancingId>
    </NonRecurringCharges>
</Offerings>
<Offerings>
    <Type>Product</Type>
    <Name Language="ZFR">Enlvement</Name>
</Offerings></ContractSummary>

XSLT：

<xsl:template match="ContractSummary">
<xsl:copy>
  <xsl:apply-templates select="@* | *[not(self::Offerings)]" />
  <xsl:apply-templates select="Offerings">
    <xsl:sort select="Type"  />
    <xsl:sort select="NonRecurringCharges"  />
  </xsl:apply-templates>
</xsl:copy>   </xsl:template>

结果，我有 xml:

<ContractSummary>falseOneTimeServiceCable AccessPostPaidCAAC0001ProductEnlvementProductCable AccessPostPaidCAAC0001</ContractSummary>

我需要xml:

<ContractSummary>
<OrderInfo>
    <IsMobileOnly>false</IsMobileOnly>
</OrderInfo>
<Offerings>
    <Type>OneTimeService</Type>
    <Name Language="NL">Cable Access</Name>
    <NonRecurringCharges>
        <Type>PostPaid</Type>
        <ThirdPartyFinancingId>CAAC0001</ThirdPartyFinancingId>
    </NonRecurringCharges>
</Offerings>
<Offerings>
    <Type>Product</Type>
    <Name Language="ZFR">Enlvement</Name>
</Offerings>
<Offerings>
    <Type>Product2</Type>
    <Name Language="NL">Cable Access</Name>
    <NonRecurringCharges>
        <Type>PostPaid</Type>
        <ThirdPartyFinancingId>CAAC0001</ThirdPartyFinancingId>
    </NonRecurringCharges>
</Offerings></ContractSummary>

Answer 1

添加身份转换作为基本步骤，例如在 XSLT 3 中通过声明 <xsl:mode on-no-match="shallow-copy"/> 或在 XSLT 1 和 2 中通过添加模板

<xsl:template match="@* | node()">
  <xsl:copy>
    <xsl:apply-templates select="@* | node()"/>
  </xsl:copy>
</xsl:template>

仅复制标签的值而不是排序时的所有标签

Copying only tags' values rather than all tags on sorting

xslt