如何调整 R 中 pivot_longer() 中的特定错误

Question

你能帮我调整一下我的 Sumpk 变量吗？不幸的是，当我运行.

时出现错误

library(dplyr)
library(tidyverse)
library(lubridate)

df1 <- structure(
  list(date1 = c("2021-06-28","2021-06-28","2021-06-28","2021-06-28"),
       date2 = c("2021-04-02","2021-04-02","2021-04-08","2021-04-08"),
       Code = c("ABC","CDE","ABC","CDE"),
       Week= c("Friday","Friday","Thursday","Thursday"),
       DR1 = c(11,17,14,13),
       DR01 = c(14,11,14,13), DR02= c(14,12,16,17),DR03= c(19,15,14,13),
       DR04 = c(15,14,13,13)),
  class = "data.frame", row.names = c(NA, -4L))
> df1
       date1      date2 Code     Week DR1 DR01 DR02 DR03 DR04
1 2021-06-28 2021-04-02  ABC   Friday  11   14   14   19   15
2 2021-06-28 2021-04-02  CDE   Friday  17   11   12   15   14
3 2021-06-28 2021-04-08  ABC Thursday  14   14   16   14   13
4 2021-06-28 2021-04-08  CDE Thursday  13   13   17   13   13
x<-df1 %>% select(starts_with("DR"))

x<-cbind(df1, setNames(df1$DR1 - x, paste0(names(x), "_PV")))
pk<-select(x, date2,Code, Week, DR1, ends_with("PV"))

med<-pk %>%
  group_by(Code, Week) %>%
  summarize(across(ends_with("PV"), median))
> med
# A tibble: 4 x 7
# Groups:   Code [2]
  Code  Week     DR1_PV DR01_PV DR02_PV DR03_PV DR04_PV
  <chr> <chr>     <dbl>   <dbl>   <dbl>   <dbl>   <dbl>
1 ABC   Friday        0      -3      -3      -8      -4
2 ABC   Thursday      0       0      -2       0       1
3 CDE   Friday        0       6       5       2       3
4 CDE   Thursday      0       0      -4       0       0

Sumpk<-df1%>%
  pivot_longer(-c(date1:Week)) %>%
  left_join(med %>% rename_with( ~str_remove(., "_PV")) %>% 
              pivot_longer(-Week, values_to = "med")) %>%
  mutate(new_value = value + med) %>%
  select(-c(value:med)) %>%
  pivot_wider(names_from = name, values_from = new_value, 
              names_glue = '{name}_{name}_PV')

Sumpk 的输出

Answer 1

在left_join部分，由于Code变量是字符，所以出现错误。如果你删除它，错误将被删除，但取决于你的目的，它可能需要以其他方式处理。

Sumpk<- df1%>%
  pivot_longer(-c(date1:Week)) %>%
  left_join(med %>% ungroup %>% select(-Code) %>% rename_with( ~str_remove(., "_PV")) %>% 
              pivot_longer(-Week, values_to = "med")) %>%
  mutate(new_value = value + med) %>%
  select(-c(value:med)) %>%
  pivot_wider(names_from = name, values_from = new_value, 
              names_glue = '{name}_{name}_PV')

head(Sumpk)
# A tibble: 6 x 12
  date1      date2 Code  Week  DR1_DR1_PV DR01_DR01_PV DR02_DR02_PV DR03_DR03_PV
  <chr>      <chr> <chr> <chr> <list>     <list>       <list>       <list>      
1 2021-06-28 2021~ ABC   Frid~ <dbl [3]>  <dbl [3]>    <dbl [3]>    <dbl [3]>   
2 2021-06-28 2021~ CDE   Satu~ <dbl [3]>  <dbl [3]>    <dbl [3]>    <dbl [3]>   
3 2021-06-28 2021~ EFG   Thur~ <dbl [2]>  <dbl [2]>    <dbl [2]>    <dbl [2]>   
4 2021-06-28 2021~ HIJ   Frid~ <dbl [3]>  <dbl [3]>    <dbl [3]>    <dbl [3]>   
5 2021-06-28 2021~ ABC   Satu~ <dbl [3]>  <dbl [3]>    <dbl [3]>    <dbl [3]>   
6 2021-06-28 2021~ CDE   Thur~ <dbl [2]>  <dbl [2]>    <dbl [2]>    <dbl [2]>   
# ... with 4 more variables: DR04_DR04_PV <list>, DR05_DR05_PV <list>,
#   DR06_DR06_PV <list>, DR07_DR07_PV <list>

Answer 2

你可以试试这个inner_join方法-

library(dplyr)

df1 %>%
  inner_join(med, by = c('Code', 'Week')) %>%
  mutate(across(DR1:DR04, ~.x + get(paste0(cur_column(), '_PV')), 
         .names = '{col}_{col}_PV')) %>%
  select(date1:Week, DR1_DR1_PV:DR04_DR04_PV)

#       date1      date2 Code     Week DR1_DR1_PV DR01_DR01_PV DR02_DR02_PV DR03_DR03_PV DR04_DR04_PV
#1 2021-06-28 2021-04-02  ABC   Friday         11           11           11           11           11
#2 2021-06-28 2021-04-02  CDE   Friday         17           17           17           17           17
#3 2021-06-28 2021-04-08  ABC Thursday         14           14           14           14           14
#4 2021-06-28 2021-04-08  CDE Thursday         13           13           13           13           13

另一种适用于动态列的方法是 -

df3 <- df1 %>%  inner_join(med, by = c('Code', 'Week'))
cols <- grep('DR', names(df1), value = TRUE)
new_cols <- paste(cols, cols, 'PV', sep = '_')
df3[new_cols] <- df1[cols] + df3[paste0(cols, '_PV')]
df3 %>% select(date1:Week, all_of(new_cols))

如何调整 R 中 pivot_longer() 中的特定错误

How to adjust specific error in pivot_longer() in R

r

tidyr