Python 迭代和创建嵌套字典

Question

我有一些数据采用以下格式 (mylist)，我正在尝试将其转换为嵌套字典，但很难使格式正确。我尝试了几种迭代和转换变体，但无法获得所需的结果。我可以使用 mylist 中的数据格式获得所需格式的数据（如所需结果所示）吗？

mylist = [
    [('floor', 'first_floor'), ('bed_room', 'room1'), ('windows', 2), ('color', 'violet')],
    [('floor', 'second_floor'), ('bed_room', 'room2'), ('windows', 4), ('color', 'violet')],
]

nest_keys = ['floor', 'bedroom']
cmd_tree = {}
for i in mylist:
    last_element = True
    for key in reversed(nest_keys):
        if last_element is True:
            cmd_tree = {key: dict([x for x in i if x[0] not in nest_keys])}
            last_element = False
        else:
            cmd_tree = {key: cmd_tree}

print(cmd_tree)

当前结果：

{'floor': {'bedroom': {'bed_room': 'room2', 'windows': 4, 'color': 'violet'}}}

想要的结果：

{'floor': {'first_floor': {'bed_room': {'room1': {'color': 'white',
                                                  'windows': 2}}},
           'second_floor': {'bed_room': {'room2': {'color': 'violet',
                                                   'windows': 4}}}}}

Answer 1

无需反向循环，遍历列表，每次初始迭代都是一个楼层，然后循环遍历其内容以创建楼层详细信息：

result = {}
br = 'bed_room'

for (_, floor_name), *details in mylist:
    result[floor_name] = {br: {}}
    
    for name, detail in details:
        if name == br:
            room = detail
            result[floor_name][br][room] = {}
        else:
            result[floor_name][br][room][name] = detail

print({'floor': result})

{'floor': {'first_floor': {'bed_room': {'room1': {'color': 'violet',
                                                  'windows': 2}}},
           'second_floor': {'bed_room': {'room2': {'color': 'violet',
                                                   'windows': 4}}}}}

Python 迭代和创建嵌套字典

Python Iterating and Creating a Nested Dictionary

python

iteration

dictionary

python-3.x