AWK。如何在分隔符之间添加相同的序号？

Question

我有一个文件如下：

Lisa with a client ID
####
Mike with a boss ID
Tim with a boss ID
Joe with a boss ID
####
Susan with a sales ID
Jenny with a sales ID
####

我希望输出为：

Group1,Lisa with a client ID
Group2,Mike with a boss ID
Group2,Tim with a boss ID
Group2,Joe with a boss ID
Group3,Susan with a sales ID
Group3,Jenny with a sales ID

我试过以下命令：

awk 'BEGIN{ RS="####"}![=12=]{ next }{printf([=12=]="Group"++i","[=12=])}' file.txt

但输出似乎只是用序列号替换####，例如：

Group1,Lisa with a client ID
Group2,
Mike with a boss ID
Tim with a boss ID
Joe with a boss ID
Group3,
Susan with a sales ID
Jenny with a sales ID
Group4

我想知道如何在分隔符之间的行的开头添加相同的序号？非常感谢！！

Answer 1

计算####出现了多少次，并在每一行中输出结果。从 1 开始计数。

awk 'BEGIN{c=1} /^####/{c++; next} {print "Group" c "," [=10=]}' file

输出：

Group1,Lisa with a client ID
Group2,Mike with a boss ID
Group2,Tim with a boss ID
Group2,Joe with a boss ID
Group3,Susan with a sales ID
Group3,Jenny with a sales ID

AWK。如何在分隔符之间添加相同的序号？

AWK. how to add the same sequential number between the separator?

awk