创建 Django 查询集以访问整个数据库

Question

更新我意识到我下面的解释有点隐藏了我真正的问题是什么。最终我想要完成的是创建一个 dashboard.html 模板并能够从我的流量和电子邮件模型中呈现 access/data。

我正在使用 Django 1.8.3 和 Python 3.4.3

我正在构建一个软件，它将接受输入的值并将它们显示在视图中 - 很简单。目前我有两个 models/views 带有单独的模板来查看数据。这按预期工作。

我还在创建一个仪表板，它应该从我的两个模型中提取数据，这就是让我悲伤的部分，试图让我的思绪环绕。我阅读了很多关于查询集的内容，但找不到关于如何在我的项目中实施我完全理解的示例。

让您了解渲染的内容；此数据是从 Google Analytics 导出的表格数据，转换为 csv，然后从 Django 管理导入到应用程序中。这个想法是能够使用 'for' 循环将数据作为列表查看，这很有效，仪表板能够制作计算数据的可视化图表。

如有任何帮助，我们将不胜感激。我不确定您需要多少信息，所以我会在下面尽可能多地提供信息。谢谢。

models.py

from django.db import models


class Traffic(models.Model):
    date = models.DateField()
    traffic = models.PositiveIntegerField(null=True)
    ifs_signups = models.IntegerField(null=True)
    campaigns = models.IntegerField(null=True)
    sales = models.PositiveIntegerField(null=True)

    def month(self):
        return self.date.strftime("%B")

    def quarter(self):
        item = self.date.strftime("%B")
        q1 = (["January", "February", "March"])
        q2 = (["April", "May", "June"])
        q3 = (["July", "August", "September"])
        q4 = (["October", "November", "December"])

        if item in q1:
            return "1st Quarter"
        elif item in q2:
            return "2nd Quarter"
        elif item in q3:
            return "3rd Quarter"
        elif item in q4:
            return "4th Quarter"
        else:
            return "No Date Specified"

    def conversions(self):
        conversion = self.sales / self.traffic
        return "%r" % conversion


class Email(models.Model):
    date = models.DateField()
    subject = models.CharField(max_length=255)
    day_of_week = models.CharField(max_length=255)
    subject_type = models.CharField(max_length=255)
    content_type = models.CharField(max_length=255)
    email_list = models.CharField(max_length=255)
    recipients = models.PositiveIntegerField(null=True)
    unsubscribes = models.PositiveIntegerField(null=True)
    bounces = models.PositiveIntegerField(null=True)
    open = models.PositiveIntegerField(null=True)
    clicks = models.PositiveIntegerField(null=True)

    def month(self):
        return self.date.strftime("%B")

    def open_rate(self):
        open_rate = self.open / self.recipients
        return "%r" % open_rate

    def click_through_rate(self):
        click_through_rate = self.clicks / self.open
        return "%r" % click_through_rate

views.py

from django.shortcuts import render, redirect
from django.views.generic import ListView
from .models import Traffic
from .models import Email


class TrafficListView(ListView):
    model = Traffic
    template_name = 'dashboard/pages/traffic.html'

    def get_context_data(self, **kwargs):
        context = super(TrafficListView, self).get_context_data(**kwargs)
        return context


class EmailListView(ListView):
    model = Email
    template_name = 'dashboard/pages/email.html'

    def get_context_data(self, **kwargs):
        context = super(EmailListView, self).get_context_data(**kwargs)
        return context

Answer 1

我建议脱离 ListView 并实现您自己的简单 TemplateView。

from myapp.models import Traffic, Email

class DashboardView(TemplateView):

    template_name = "dashboard/pages/dashboard.html"

    def get_context_data(self, **kwargs):
        context = super(DashboardView, self).get_context_data(**kwargs)
        context['email_list'] = Email.objects.all()
        context['traffic_list'] = Traffic.objects.all()
        return context

创建 Django 查询集以访问整个数据库

Creating Django Query Sets to Access Entire Database

django

django-templates

django-models

django-views

python-3.x