按日期间隔查找重复项
Find duplicates by date interval
我有下面的前 3 列 table，我想获得第 4 列 (CLASHING)。如果按帐户分区，开始日期和结束日期之间的时间段发生冲突，我想将其标记为 'X'。
ACCOUNT START END CLASHING
----------------------------------------
1 30-Sep-21 28-Oct-21 NO
1 01-Jul-21 20-Aug-21 NO
2 30-Jul-21 28-Oct-21 YES
2 01-Jul-21 20-Aug-21 YES
您可以使用：
SELECT t.*,
CASE
WHEN EXISTS(SELECT 1
FROM table_name x
WHERE x."START" < t."END"
AND x."END" > t."START"
AND x.account = t.account
AND x.ROWID != t.ROWID)
THEN 'YES'
ELSE 'NO'
END AS clashing
FROM table_name t
其中，对于示例数据：
CREATE TABLE table_name (ACCOUNT, "START", "END") AS
SELECT 1, DATE '2021-09-30', DATE '2021-10-28' FROM DUAL UNION ALL
SELECT 1, DATE '2021-07-21', DATE '2021-08-20' FROM DUAL UNION ALL
SELECT 2, DATE '2021-07-30', DATE '2021-10-28' FROM DUAL UNION ALL
SELECT 2, DATE '2021-07-01', DATE '2021-08-20' FROM DUAL;
输出：
ACCOUNT
START
END
CLASHING
1
30-SEP-21
28-OCT-21
NO
1
21-JUL-21
20-AUG-21
NO
2
30-JUL-21
28-OCT-21
YES
2
01-JUL-21
20-AUG-21
YES
db<>fiddle here
我有下面的前 3 列 table，我想获得第 4 列 (CLASHING)。如果按帐户分区，开始日期和结束日期之间的时间段发生冲突，我想将其标记为 'X'。
ACCOUNT START END CLASHING
----------------------------------------
1 30-Sep-21 28-Oct-21 NO
1 01-Jul-21 20-Aug-21 NO
2 30-Jul-21 28-Oct-21 YES
2 01-Jul-21 20-Aug-21 YES
您可以使用：
SELECT t.*,
CASE
WHEN EXISTS(SELECT 1
FROM table_name x
WHERE x."START" < t."END"
AND x."END" > t."START"
AND x.account = t.account
AND x.ROWID != t.ROWID)
THEN 'YES'
ELSE 'NO'
END AS clashing
FROM table_name t
其中，对于示例数据：
CREATE TABLE table_name (ACCOUNT, "START", "END") AS
SELECT 1, DATE '2021-09-30', DATE '2021-10-28' FROM DUAL UNION ALL
SELECT 1, DATE '2021-07-21', DATE '2021-08-20' FROM DUAL UNION ALL
SELECT 2, DATE '2021-07-30', DATE '2021-10-28' FROM DUAL UNION ALL
SELECT 2, DATE '2021-07-01', DATE '2021-08-20' FROM DUAL;
输出：
ACCOUNT START END CLASHING 1 30-SEP-21 28-OCT-21 NO 1 21-JUL-21 20-AUG-21 NO 2 30-JUL-21 28-OCT-21 YES 2 01-JUL-21 20-AUG-21 YES
db<>fiddle here