使用 Python 仅获取 Azure Data Lake 目录中的子文件夹名称列表
To get only list of subfolder names in Directory in Azure Data Lake using Python
我在名为 infaqa 的 Azure 数据湖容器中有数据,在 infaqa 中有目录,路径如下:
`infqa/EIM//Sales/Raw/APXTConga4__Composer_Setting__mdt、infqa/EIM//Sales/Raw/Account等
我正在使用 Azure 笔记本和 blobserviceclient to list blobs
等库,但我看到所有子文件夹列表和子文件夹列表都在继续列出。当我从下面显示的输出 ['APXTConga4__Composer_Setting__mdt','Account'...]
中仅查找列表中的子文件夹名称时
Input:
blobPrefix = "/EIM/Sales/Raw/"
mylist=[]
objects=[]
blob_list = container_client.list_blobs(blobPrefix)
for blob in blob_list:
mylist.append(blob.name)
print(blob.name)
Ouptut:
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt/2020
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt/2020/12
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt/2020/12/02
EIM/Sales/Raw/Account
EIM/Sales/Raw/Account/2020
EIM/Sales/Raw/Account/2020/12
EIM/Sales/Raw/Account/2020/12/02
试试这个解决方案,我在我的系统中试过
我的文件夹结构类似于 test
容器和 account
是文件夹
1)test/account/main/sub1/
2)test/account/test1/sub2
3)test/account/test2/sub3
from azure.storage.blob import BlobServiceClient
import os
source_key = 'Key'
source_account_name = 'Account Name'
block_blob_service = BlobServiceClient(
account_url=f'https://{source_account_name}.blob.core.windows.net/', credential=source_key)
source_container_client = block_blob_service.get_container_client(
'Container name')
result=[]
allfolders=[]
generator =source_container_client.list_blobs("account")
for file in source_container_client.walk_blobs('account/', delimiter='/'):
print(file.name)
text=file.name
result.append(text)
for data in result:
allfolders.append(data.replace("account/",""))
print(allfolders)
for res in allfolders:
print(res)
输出
存储帐户中的文件夹结构
能够获取所有子文件夹名称
我在名为 infaqa 的 Azure 数据湖容器中有数据,在 infaqa 中有目录,路径如下: `infqa/EIM//Sales/Raw/APXTConga4__Composer_Setting__mdt、infqa/EIM//Sales/Raw/Account等
我正在使用 Azure 笔记本和 blobserviceclient to list blobs
等库,但我看到所有子文件夹列表和子文件夹列表都在继续列出。当我从下面显示的输出 ['APXTConga4__Composer_Setting__mdt','Account'...]
中仅查找列表中的子文件夹名称时
Input:
blobPrefix = "/EIM/Sales/Raw/"
mylist=[]
objects=[]
blob_list = container_client.list_blobs(blobPrefix)
for blob in blob_list:
mylist.append(blob.name)
print(blob.name)
Ouptut:
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt/2020
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt/2020/12
EIM/Sales/Raw/APXTConga4__Composer_Setting__mdt/2020/12/02
EIM/Sales/Raw/Account
EIM/Sales/Raw/Account/2020
EIM/Sales/Raw/Account/2020/12
EIM/Sales/Raw/Account/2020/12/02
试试这个解决方案,我在我的系统中试过
我的文件夹结构类似于 test
容器和 account
是文件夹
1)test/account/main/sub1/
2)test/account/test1/sub2
3)test/account/test2/sub3
from azure.storage.blob import BlobServiceClient
import os
source_key = 'Key'
source_account_name = 'Account Name'
block_blob_service = BlobServiceClient(
account_url=f'https://{source_account_name}.blob.core.windows.net/', credential=source_key)
source_container_client = block_blob_service.get_container_client(
'Container name')
result=[]
allfolders=[]
generator =source_container_client.list_blobs("account")
for file in source_container_client.walk_blobs('account/', delimiter='/'):
print(file.name)
text=file.name
result.append(text)
for data in result:
allfolders.append(data.replace("account/",""))
print(allfolders)
for res in allfolders:
print(res)
输出
存储帐户中的文件夹结构
能够获取所有子文件夹名称