通过 while 循环在 hashmap 中添加 <Key, Value> 但不起作用

Adding <Key, Value> in hashmap by while loop but not working

我有以下 CSV 文件,我想创建一个 hashmap,其中唯一键应该是每一行的第一个值,值应该是一个 arraylist,其中包含第一行下每一行的信息这一行的价值。 CSV 示例如下:

1,0
1,1
1,2
1,3
1,4
2,0
2,1
2,2
4,0
10,0
10,1
10,2
10,3
10,4
10,5

理想情况下,我希望最终的 ArrayList 类似于:

{1=[1,0, 1,1, 1,2, 1,3, 1,4], 2=[2,0, 2,1, 2,2], 4=[4,0], 10=[10,0, 10,1, 10,2, 10,3, 10,4, 10, 5]}

下面是我用来尝试通过 while 循环解决这个问题的代码

public static void main(String[] args) {
        int activityRecord = 1;
        String activitiesFile = "scenarios/BrusselsPopulationFromR/BrusselsActivities.csv";

        HashMap<Integer, ArrayList<String>> idAndAllActivities = new HashMap<>();
        try {
            BufferedReader activityReader = new BufferedReader(new FileReader(activitiesFile));
            String agentActivity = null;
            ArrayList activities = new ArrayList();

            while ((agentActivity = activityReader.readLine()) != null){
                String activityWithAllInfo = agentActivity;
                String[] activitySpilted = agentActivity.split(",");
                int activityAgentID = Integer.parseInt(activitySpilted[0]);

                if (activityAgentID == activityRecord){
                    activities.add(activityWithAllInfo);
                } else if (activityAgentID != activityRecord){
                    idAndAllActivities.put(activityRecord, activities);
                    activityRecord = activityAgentID;
                    activities.clear();
                    activities.add(activityWithAllInfo);
                }
            }

        } catch (IOException e) {
            e.printStackTrace();
        }

        System.out.println(idAndAllActivities);
    }

基本上,我尝试证明是否activityAgentID == activityRecord(最初为1),如果不同,我会将添加到hashmap并清除activities arrayList .然而,这个程序的输出是这样的:

{1=[10,0, 10,1, 10,2, 10,3, 10,4, 10,5], 2=[10,0, 10,1, 10,2, 10,3, 10,4, 10,5], 4=[10,0, 10,1, 10,2, 10,3, 10,4, 10,5]}

这不是我想要的,我尝试调试它,但我找不到原因,因为我对 Java 真的很陌生......我想知道你是否知道如何解决这个问题?任何提示将不胜感激!

谢谢!

您的代码中的问题是您重用了 activities 数组。活动数组和 HashMap 中分配的数组都指向相同的引用,因此如果更新 activities 数组,地图中的所有条目也将更新。

假设文件中的密钥已排序,您可以像这样稍微调整一下代码

HashMap<Integer, ArrayList<String>> idAndAllActivities = new HashMap<>();
try {
    BufferedReader activityReader = new BufferedReader(new FileReader(activitiesFile));
    String agentActivity = null;
    ArrayList<String> activities = new ArrayList<>();

    while ((agentActivity = activityReader.readLine()) != null){
          String[] activitySpilted = agentActivity.split(",");
          int activityAgentID = Integer.parseInt(activitySpilted[0]);

          if (activityAgentID == activityRecord){
               activities.add(agentActivity);
          } else {
               idAndAllActivities.put(activityRecord, activities);
               activityRecord = activityAgentID;
               activities = new ArrayList<>();
               activities.add(agentActivity);
          }
     }

     idAndAllActivities.put(activityRecord, activities);

} catch (IOException e) {
        e.printStackTrace();
}

System.out.println(idAndAllActivities);

请注意,您不需要这个:String activityWithAllInfo = agentActivity; 因为 String 在 Java

中是不可变的

你可以换一种方式。如果 CSV 文件的顺序更改如下,则不会中断的方法如下:

1,0
1,1
2,0
1,2
10,0
10,1
10,2
1,3
1,4
2,1
2,2
4,0
10,3
10,4
10,5

使用此 CSV,您的代码将失败,因为您依赖 CSV 文件将所有 1 activity 记录放在一起。为了解决这个问题,请尝试以下操作(注意您不再依赖 activityRecord):

public static void main(String[] args) {
    String activitiesFile = "scenarios/BrusselsPopulationFromR/BrusselsActivities.csv";

    HashMap<Integer, ArrayList<String>> idAndAllActivities = new HashMap<>();
    try {
        BufferedReader activityReader = new BufferedReader(new FileReader(activitiesFile));
        String agentActivity = null;

        while ((agentActivity = activityReader.readLine()) != null){
            String activityWithAllInfo = agentActivity;
            String[] activitySpilted = agentActivity.split(",");
            int activityAgentID = Integer.parseInt(activitySpilted[0]);

            if (idAndAllActivities.containsKey(activityAgentID)){
                ArrayList existentActivities = idAndAllActivities.get(activityAgentID);
                existentActivities.add(activityWithAllInfo);
            } else {
                ArrayList activities = new ArrayList();
                activities.add(activityWithAllInfo);
                idAndAllActivities.put(activityAgentID, activities);
            }
        }

    } catch (IOException e) {
        e.printStackTrace();
    }

    System.out.println(idAndAllActivities);
}

假设您使用的是 Java 8 或更高版本,在 Files.linesCollectors.groupingBy 的帮助下可以大大简化任务并使代码更具可读性:

import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Paths;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
import java.util.stream.Stream;

public class Example {

    public static void main(String[] args) {
        String activitiesFile = "scenarios/BrusselsPopulationFromR/BrusselsActivities.csv";
        Map<Integer,List<String>> idAndAllActivities = null;
        try (Stream<String> content = Files.lines(Paths.get(activitiesFile))) {
            idAndAllActivities = content.collect(Collectors.groupingBy(row -> Integer.parseInt(row.split(",")[0])));
        } catch (IOException e) {
            e.printStackTrace();
        }
        System.out.println(idAndAllActivities);
    }
}