难以理解 PHP POST 到 REST API - 混合数组和对象
Difficulty to understand PHP POST to REST API - mixed array and objects
我正在尝试 POST 数据到 REST API。
在 Postman 上我可以 POST 成功，JSON 正文是：
{
"version": 0,
"roles": {
"customer": {
}
},
"person": {
"firstName": "Inge",
"lastName": "Musterfrau"
},
"emailAddresses" :{
"private" : [
"email@domain.com"
]
},
"addresses": {
"billing": [
{
"supplement": null,
"street": "aaa",
"zip": "12345",
"city": "Berlin",
"countryCode": "DE"
}
]
}
}
我的问题是地址计费。我不知道如何正确创建 object/array 以便 API 接受它。
我正在像下面这样在 PHO 上构建参数：
$billingAddr = array(
"supplement" => $billingAddress["streetDetails"],
"street" => $billingAddress["street"],
"zip" => $billingAddress["zipCode"],
"city" => $billingAddress["city"],
"countryCode" => $billingAddress["country"],
);
$params = [
"version" => 0,
"roles" => $roles,
"person" => $person,
"emailAddresses" => $emailAddresses,
"addresses" => [
"billing" => $billingAddr
]
];
我收到一个错误：“missing_entity - 地址 - validation_failure”。
我认为我的问题是创建混合对象地址、数组计费。
因此，严格按照 PHP 示例，执行 json_encode 的输出表明地址的结构并不完全相同。
请注意，我没有 PHP 示例中其余大部分 json 信息的数据，因此下面的输出示例严格集中在 addresses部分。
Before JSON change:
echo json_encode($params, JSON_PRETTY_PRINT);
{
"version": 0,
"roles": null,
"person": null,
"emailAddresses": null,
"addresses": {
"billing": {
"supplement": null,
"street": null,
"zip": null,
"city": null,
"countryCode": null
}
}
}
...其中，请注意帐单没有 [] 个字符，就像使用邮递员发送的一样。
不过不用担心，这很容易解决。应更改地址部分以获取账单地址数组，如下所示：
"addresses" => [
"billing" => [$billingAddr]
]
然后 运行 应用该更改的重新检查显示：
After JSON change:
echo json_encode($params, JSON_PRETTY_PRINT);
{
"version": 0,
"roles": null,
"person": null,
"emailAddresses": null,
"addresses": {
"billing": [
{
"supplement": null,
"street": null,
"zip": null,
"city": null,
"countryCode": null
}
]
}
}
这应该有助于实现预期的格式。
这是 fiddle example 以防您需要另一个 PHP 版本来检查。 fiddle 默认为 8.0.1
对象属性和关联数组很容易直接access/declare；但是，当您需要将数据推送到索引子数组时，您可以使用 [] 语法或 array_push().
如果您想在这段代码中建立更多的可维护性，您可以将可变长度子数组构建为单独的变量，然后在 json_encoding.
之前将它们输入到主数组中
$version = 0;
$roles = ['customer' => []];
$person = [
'firstName' => 'Inge',
'lastName' => 'Musterfrau'
];
$emailAddresses = [
'private' => [
'email@domain.com',
]
];
$billingAddresses[] = [
'supplement' => $billingAddress["streetDetails"],
'street' => $billingAddress["street"],
'zip' => $billingAddress["zipCode"],
'city' => $billingAddress["city"],
'countryCode' => $billingAddress["country"]
];
// use $billingAddresses[] again to push another subarray into $billing
$data = [
'version' => $version,
'roles' => $roles,
'person' => $person,
'emailAddresses' => $emailAddresses,
'addresses' => [
'billing' => $billingAddresses
]
]
这将创建您的 array/json :
$arr['version'] = "0";
$arr['roles']['customer'] = [];
$arr['person']['firstName'] = "Inge";
$arr['person']['lastName'] = "Musterfrau";
$arr['emailAddresses']['private'][] = "email@domain.com";
$arr['addresses']['billing'][0]['supplement'] = "";
$arr['addresses']['billing'][0]['street'] = "aaa";
$arr['addresses']['billing'][0]['zip'] = "12345";
$arr['addresses']['billing'][0]['city'] = "Berlin";
$arr['addresses']['billing'][0]['countryCode'] = "DE";
$newJson = json_encode($arr);
然后你 json_encode 它和瞧完美 json 而且非常简单！
查看 json 的最好和最简单的方法（至少在我看来：）是作为一个数组！ （使用浏览器并在此处回显“”并不可耻！）- 我们将构建一个相同的数组并将其 json 返回！
一旦我们将 json 视为一个数组，我们就会以一种非常简单的方式构建相同的数组 这里是完整的代码示例，逐步进行：
<?php
/*Our original json */
$json = '{
"version": 0,
"roles": {
"customer": {
}
},
"person": {
"firstName": "Inge",
"lastName": "Musterfrau"
},
"emailAddresses" :{
"private" : [
"email@domain.com"
]
},
"addresses": {
"billing": [
{
"supplement": null,
"street": "aaa",
"zip": "12345",
"city": "Berlin",
"countryCode": "DE"
}
]
}
}';
$array = json_decode($json,true);
echo '<pre>';
/* original array */
echo "original array: ";
print_r($array);
echo '<pre>';
/* now lets create the same array with less fuss?! */
$arr['version'] = "0";
$arr['roles']['customer'] = [];
$arr['person']['firstName'] = "Inge";
$arr['person']['lastName'] = "Musterfrau";
$arr['emailAddresses']['private'][] = "email@domain.com";
$arr['addresses']['billing'][0]['supplement'] = "";
$arr['addresses']['billing'][0]['street'] = "aaa";
$arr['addresses']['billing'][0]['zip'] = "12345";
$arr['addresses']['billing'][0]['city'] = "Berlin";
$arr['addresses']['billing'][0]['countryCode'] = "DE";
/* the new array: */
echo "our newly created array: ";
echo '<pre>';
print_r($arr);
echo '<pre>';
/* back to json */
echo "new Json: ";
echo '<pre>';
$newJson = json_encode($arr);
print_r($newJson);
这将 return:
original array: Array
(
[version] => 0
[roles] => Array
(
[customer] => Array
(
)
)
[person] => Array
(
[firstName] => Inge
[lastName] => Musterfrau
)
[emailAddresses] => Array
(
[private] => Array
(
[0] => email@domain.com
)
)
[addresses] => Array
(
[billing] => Array
(
[0] => Array
(
[supplement] =>
[street] => aaa
[zip] => 12345
[city] => Berlin
[countryCode] => DE
)
)
)
)
our newly created array:
Array
(
[version] => 0
[roles] => Array
(
[customer] => Array
(
)
)
[person] => Array
(
[firstName] => Inge
[lastName] => Musterfrau
)
[emailAddresses] => Array
(
[private] => Array
(
[0] => email@domain.com
)
)
[addresses] => Array
(
[billing] => Array
(
[0] => Array
(
[supplement] =>
[street] => aaa
[zip] => 12345
[city] => Berlin
[countryCode] => DE
)
)
)
)
new Json:
{"version":"0","roles":{"customer":[]},"person":{"firstName":"Inge","lastName":"Musterfrau"},"emailAddresses":{"private":["email@domain.com"]},"addresses":{"billing":[{"supplement":"","street":"aaa","zip":"12345","city":"Berlin","countryCode":"DE"}]}}
以这种方式构建数组可以非常简单 - 几乎是线性的！ :)
我正在尝试 POST 数据到 REST API。
在 Postman 上我可以 POST 成功，JSON 正文是：
{
"version": 0,
"roles": {
"customer": {
}
},
"person": {
"firstName": "Inge",
"lastName": "Musterfrau"
},
"emailAddresses" :{
"private" : [
"email@domain.com"
]
},
"addresses": {
"billing": [
{
"supplement": null,
"street": "aaa",
"zip": "12345",
"city": "Berlin",
"countryCode": "DE"
}
]
}
}
我的问题是地址计费。我不知道如何正确创建 object/array 以便 API 接受它。
我正在像下面这样在 PHO 上构建参数：
$billingAddr = array(
"supplement" => $billingAddress["streetDetails"],
"street" => $billingAddress["street"],
"zip" => $billingAddress["zipCode"],
"city" => $billingAddress["city"],
"countryCode" => $billingAddress["country"],
);
$params = [
"version" => 0,
"roles" => $roles,
"person" => $person,
"emailAddresses" => $emailAddresses,
"addresses" => [
"billing" => $billingAddr
]
];
我收到一个错误：“missing_entity - 地址 - validation_failure”。
我认为我的问题是创建混合对象地址、数组计费。
因此，严格按照 PHP 示例，执行 json_encode 的输出表明地址的结构并不完全相同。
请注意，我没有 PHP 示例中其余大部分 json 信息的数据，因此下面的输出示例严格集中在 addresses部分。
Before JSON change:
echo json_encode($params, JSON_PRETTY_PRINT);
{
"version": 0,
"roles": null,
"person": null,
"emailAddresses": null,
"addresses": {
"billing": {
"supplement": null,
"street": null,
"zip": null,
"city": null,
"countryCode": null
}
}
}
...其中，请注意帐单没有 [] 个字符，就像使用邮递员发送的一样。
不过不用担心，这很容易解决。应更改地址部分以获取账单地址数组，如下所示：
"addresses" => [
"billing" => [$billingAddr]
]
然后 运行 应用该更改的重新检查显示：
After JSON change:
echo json_encode($params, JSON_PRETTY_PRINT);
{
"version": 0,
"roles": null,
"person": null,
"emailAddresses": null,
"addresses": {
"billing": [
{
"supplement": null,
"street": null,
"zip": null,
"city": null,
"countryCode": null
}
]
}
}
这应该有助于实现预期的格式。
这是 fiddle example 以防您需要另一个 PHP 版本来检查。 fiddle 默认为 8.0.1
对象属性和关联数组很容易直接access/declare；但是，当您需要将数据推送到索引子数组时，您可以使用 [] 语法或 array_push().
如果您想在这段代码中建立更多的可维护性，您可以将可变长度子数组构建为单独的变量，然后在 json_encoding.
之前将它们输入到主数组中$version = 0;
$roles = ['customer' => []];
$person = [
'firstName' => 'Inge',
'lastName' => 'Musterfrau'
];
$emailAddresses = [
'private' => [
'email@domain.com',
]
];
$billingAddresses[] = [
'supplement' => $billingAddress["streetDetails"],
'street' => $billingAddress["street"],
'zip' => $billingAddress["zipCode"],
'city' => $billingAddress["city"],
'countryCode' => $billingAddress["country"]
];
// use $billingAddresses[] again to push another subarray into $billing
$data = [
'version' => $version,
'roles' => $roles,
'person' => $person,
'emailAddresses' => $emailAddresses,
'addresses' => [
'billing' => $billingAddresses
]
]
这将创建您的 array/json :
$arr['version'] = "0";
$arr['roles']['customer'] = [];
$arr['person']['firstName'] = "Inge";
$arr['person']['lastName'] = "Musterfrau";
$arr['emailAddresses']['private'][] = "email@domain.com";
$arr['addresses']['billing'][0]['supplement'] = "";
$arr['addresses']['billing'][0]['street'] = "aaa";
$arr['addresses']['billing'][0]['zip'] = "12345";
$arr['addresses']['billing'][0]['city'] = "Berlin";
$arr['addresses']['billing'][0]['countryCode'] = "DE";
$newJson = json_encode($arr);
然后你 json_encode 它和瞧完美 json 而且非常简单！
查看 json 的最好和最简单的方法（至少在我看来：）是作为一个数组！ （使用浏览器并在此处回显“”并不可耻！）- 我们将构建一个相同的数组并将其 json 返回！
一旦我们将 json 视为一个数组，我们就会以一种非常简单的方式构建相同的数组 这里是完整的代码示例，逐步进行：
<?php
/*Our original json */
$json = '{
"version": 0,
"roles": {
"customer": {
}
},
"person": {
"firstName": "Inge",
"lastName": "Musterfrau"
},
"emailAddresses" :{
"private" : [
"email@domain.com"
]
},
"addresses": {
"billing": [
{
"supplement": null,
"street": "aaa",
"zip": "12345",
"city": "Berlin",
"countryCode": "DE"
}
]
}
}';
$array = json_decode($json,true);
echo '<pre>';
/* original array */
echo "original array: ";
print_r($array);
echo '<pre>';
/* now lets create the same array with less fuss?! */
$arr['version'] = "0";
$arr['roles']['customer'] = [];
$arr['person']['firstName'] = "Inge";
$arr['person']['lastName'] = "Musterfrau";
$arr['emailAddresses']['private'][] = "email@domain.com";
$arr['addresses']['billing'][0]['supplement'] = "";
$arr['addresses']['billing'][0]['street'] = "aaa";
$arr['addresses']['billing'][0]['zip'] = "12345";
$arr['addresses']['billing'][0]['city'] = "Berlin";
$arr['addresses']['billing'][0]['countryCode'] = "DE";
/* the new array: */
echo "our newly created array: ";
echo '<pre>';
print_r($arr);
echo '<pre>';
/* back to json */
echo "new Json: ";
echo '<pre>';
$newJson = json_encode($arr);
print_r($newJson);
这将 return:
original array: Array
(
[version] => 0
[roles] => Array
(
[customer] => Array
(
)
)
[person] => Array
(
[firstName] => Inge
[lastName] => Musterfrau
)
[emailAddresses] => Array
(
[private] => Array
(
[0] => email@domain.com
)
)
[addresses] => Array
(
[billing] => Array
(
[0] => Array
(
[supplement] =>
[street] => aaa
[zip] => 12345
[city] => Berlin
[countryCode] => DE
)
)
)
)
our newly created array:
Array
(
[version] => 0
[roles] => Array
(
[customer] => Array
(
)
)
[person] => Array
(
[firstName] => Inge
[lastName] => Musterfrau
)
[emailAddresses] => Array
(
[private] => Array
(
[0] => email@domain.com
)
)
[addresses] => Array
(
[billing] => Array
(
[0] => Array
(
[supplement] =>
[street] => aaa
[zip] => 12345
[city] => Berlin
[countryCode] => DE
)
)
)
)
new Json:
{"version":"0","roles":{"customer":[]},"person":{"firstName":"Inge","lastName":"Musterfrau"},"emailAddresses":{"private":["email@domain.com"]},"addresses":{"billing":[{"supplement":"","street":"aaa","zip":"12345","city":"Berlin","countryCode":"DE"}]}}
以这种方式构建数组可以非常简单 - 几乎是线性的！ :)