连接 url + dtype: string
Concatenate url + dtype: string
我正在尝试将 url 与字符串列表连接起来,如下所示:
但是我收到错误...任何人都可以帮忙
密码是:
import pandas as pd
import numpy as np
from bs4 import BeautifulSoup as soup
from urllib.request import Request, urlopen
data = pd.read_csv("fornews_list.csv")
data['Symbol'] = data['Symbol'].astype("string")
col = data.head(len(data))
col
clmn = list(col)
for i in col:
print(col[i])
榜单:
0 EVK
1 SGRP
2 CRTD
3 PHCF
4 NXTD
5 GREE
6 AUUDW
7 GROM
8 VECT
9 IMPL
10 CRXT
11 FCUV
12 BKKT
13 NURO
Name: Symbol, dtype: string
url = {"http://finance.com/quote.ashx?t=" + col[i].text}
print(url)
尝试创建一个新列:
data['urls'] = data['Symbol'].apply(lambda x: "http://finance.com/quote.ashx?t=" + x)
或者只获取包含所有 url 的列表:
urls = ["http://finance.com/quote.ashx?t=" + x for x in data['Symbol'].tolist()]
完整代码:
import pandas as pd
data = pd.read_csv("fornews_list.csv")
urls = ["http://finance.com/quote.ashx?t=" + x for x in data['Symbol'].tolist()]
print(urls)
我正在尝试将 url 与字符串列表连接起来,如下所示: 但是我收到错误...任何人都可以帮忙
密码是:
import pandas as pd
import numpy as np
from bs4 import BeautifulSoup as soup
from urllib.request import Request, urlopen
data = pd.read_csv("fornews_list.csv")
data['Symbol'] = data['Symbol'].astype("string")
col = data.head(len(data))
col
clmn = list(col)
for i in col:
print(col[i])
榜单:
0 EVK
1 SGRP
2 CRTD
3 PHCF
4 NXTD
5 GREE
6 AUUDW
7 GROM
8 VECT
9 IMPL
10 CRXT
11 FCUV
12 BKKT
13 NURO
Name: Symbol, dtype: string
url = {"http://finance.com/quote.ashx?t=" + col[i].text}
print(url)
尝试创建一个新列:
data['urls'] = data['Symbol'].apply(lambda x: "http://finance.com/quote.ashx?t=" + x)
或者只获取包含所有 url 的列表:
urls = ["http://finance.com/quote.ashx?t=" + x for x in data['Symbol'].tolist()]
完整代码:
import pandas as pd
data = pd.read_csv("fornews_list.csv")
urls = ["http://finance.com/quote.ashx?t=" + x for x in data['Symbol'].tolist()]
print(urls)