从列表中选择随机函数

Question

我已经为“谁想成为百万富翁”类型的游戏定义了几个变量，其中包含问题、答案和类别（奖金金额）。然后我有这个功能，它根据这些问题、答案和诸如此类的东西运行。我尝试通过随机播放、选择、选择来使用 python 的随机函数，但没有成功。

Answer 1

您放入列表的不是函数，而是已经调用该函数的结果 -- 构建列表本身的行为在您有机会之前调用了 questionnaire 三次从中挑选一个元素。

将每个问题放入一个对象中，而不是拥有一组唯一的命名变量，这样可以更容易地选择一个随机问题作为一个单元。您可以为此使用 dict；我一般用NamedTuple.

from random import choice
from typing import List, NamedTuple, Tuple


class Question(NamedTuple):
    question: str
    answers: List[str]
    correct: str
    amount: int
    cat: int


questions = [
    Question(
        "QUESTION: What is the biggest currency in Europe?",
        ["A) Crown", "B) Peso", "C) Dolar", "D) Euro"],
        "D", 25, 1
    ),
    Question(
        "QUESTION: What is the biggest mountain in the world?",
        ["A) Everest", "B) Montblanc", "C) Popocatepepl", "D) K2"],
        "A", 25, 2
    ),
    Question(
        "QUESTION: What is the capital of Brasil?",
        ["A) Rio de Janeiro", "B) Brasilia", "C) Sao Paolo", "D) Recife"],
        "B", 25, 3
    ),
]


def questionnaire(q: Question) -> Tuple[int, bool]:
    """Presents the user with the given question.
    Returns winnings and whether to continue the game."""
    print(q.question)
    for answer in q.answers:
        print(answer)
    usr_input_answer = input(
        " What's your answer? "
        "Please select between A, B, C, D or R for Retirement. "
    ).upper()
    if usr_input_answer == q.correct:
        return q.amount, True
    elif usr_input_answer == "R":
        print("Congratulations on retirement!")
    else:
        print("Game over!")
    return 0, False


money = 0
keep_playing = True
while keep_playing:
    winnings, keep_playing = questionnaire(choice(questions))
    money += winnings

Answer 2

首先： 我建议您创建并保存所有问题 dictionary.

其次： 在 rnd.choice = 中，您尝试通过编写 = 来覆盖函数，该函数用于为等式之前的事物赋值标记。尝试查找 here.

最后：函数questionnaire()没有return一个值，所以你不想像rnd.choice=([questionnaire(question1,answers1,correct1,amount1,cat1), ...那样使用它

从列表中选择随机函数

Choosing random function from a list

python

random

loops