TypeError: Ui_MainWindow.on_click() missing 1 required positional argument: 'pressed'
TypeError: Ui_MainWindow.on_click() missing 1 required positional argument: 'pressed'
所以我试图制作一个程序,当用户点击屏幕上的任何地方时,它会告诉用户他的鼠标位置,但我收到错误:类型错误:Ui_MainWindow.on_click() 缺少 1 个必需的位置参数:'pressed'
我不明白为什么会这样,我尝试在 on_click 函数中切换“self”变量的位置,但它没有修复它,我需要 self 参数
from PyQt5 import QtCore, QtGui, QtWidgets
from PIL import ImageGrab
from pynput import mouse
import pyautogui
import time
class Ui_MainWindow(object):
def setupUi(self, MainWindow):
MainWindow.setObjectName("MainWindow")
MainWindow.resize(306, 145)
self.centralwidget = QtWidgets.QWidget(MainWindow)
self.centralwidget.setObjectName("centralwidget")
self.label_x = QtWidgets.QLabel(self.centralwidget)
self.label_x.setGeometry(QtCore.QRect(70, 90, 71, 41))
self.label_x.setScaledContents(False)
self.label_x.setAlignment(QtCore.Qt.AlignCenter)
self.label_x.setWordWrap(False)
self.label_x.setObjectName("label_x")
self.label_y = QtWidgets.QLabel(self.centralwidget)
self.label_y.setGeometry(QtCore.QRect(160, 90, 71, 41))
self.label_y.setScaledContents(False)
self.label_y.setAlignment(QtCore.Qt.AlignCenter)
self.label_y.setWordWrap(False)
self.label_y.setObjectName("label_y")
self.button = QtWidgets.QPushButton(self.centralwidget)
self.button.setGeometry(QtCore.QRect(90, 20, 111, 61))
self.button.setObjectName("button")
MainWindow.setCentralWidget(self.centralwidget)
self.retranslateUi(MainWindow)
QtCore.QMetaObject.connectSlotsByName(MainWindow)
self.button.clicked.connect(self.onPosButtonClick)
def retranslateUi(self, MainWindow):
_translate = QtCore.QCoreApplication.translate
MainWindow.setWindowTitle(_translate("MainWindow", "Bot"))
self.label_x.setText(_translate("MainWindow", "0"))
self.label_y.setText(_translate("MainWindow", "0"))
self.button.setText(_translate("MainWindow", "Pick Location"))
def on_click(self, x, y, button, pressed):
if pressed:
print('{0} at {1}'.format(
'Pressed' if pressed else 'Released',
(x, y)))
#self.label_x.setText(QtCore.QCoreApplication.translate("MainWindow", str(x)))
#self.label_y.setText(QtCore.QCoreApplication.translate("MainWindow", str(y)))
mouse.Listener.stop()
listener = mouse.Listener(on_click=on_click)
def onPosButtonClick(self):
self.listener.start()
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
MainWindow = QtWidgets.QMainWindow()
ui = Ui_MainWindow()
ui.setupUi(MainWindow)
MainWindow.show()
sys.exit(app.exec_())
新 python 顺便说一句
因为你的监听器(on_click
)是一个class成员,你必须在设置回调时提供一个对象。这意味着 listener
不能像现在那样成为 class 变量。相反,您应该在 setupUi
函数中执行此操作:
self.listener = mouse.Listener(on_click=self.on_click)
但是,您根本不需要为此使用 pynput
。 Qt可以做这种鼠标捕获。
所以我试图制作一个程序,当用户点击屏幕上的任何地方时,它会告诉用户他的鼠标位置,但我收到错误:类型错误:Ui_MainWindow.on_click() 缺少 1 个必需的位置参数:'pressed' 我不明白为什么会这样,我尝试在 on_click 函数中切换“self”变量的位置,但它没有修复它,我需要 self 参数
from PyQt5 import QtCore, QtGui, QtWidgets
from PIL import ImageGrab
from pynput import mouse
import pyautogui
import time
class Ui_MainWindow(object):
def setupUi(self, MainWindow):
MainWindow.setObjectName("MainWindow")
MainWindow.resize(306, 145)
self.centralwidget = QtWidgets.QWidget(MainWindow)
self.centralwidget.setObjectName("centralwidget")
self.label_x = QtWidgets.QLabel(self.centralwidget)
self.label_x.setGeometry(QtCore.QRect(70, 90, 71, 41))
self.label_x.setScaledContents(False)
self.label_x.setAlignment(QtCore.Qt.AlignCenter)
self.label_x.setWordWrap(False)
self.label_x.setObjectName("label_x")
self.label_y = QtWidgets.QLabel(self.centralwidget)
self.label_y.setGeometry(QtCore.QRect(160, 90, 71, 41))
self.label_y.setScaledContents(False)
self.label_y.setAlignment(QtCore.Qt.AlignCenter)
self.label_y.setWordWrap(False)
self.label_y.setObjectName("label_y")
self.button = QtWidgets.QPushButton(self.centralwidget)
self.button.setGeometry(QtCore.QRect(90, 20, 111, 61))
self.button.setObjectName("button")
MainWindow.setCentralWidget(self.centralwidget)
self.retranslateUi(MainWindow)
QtCore.QMetaObject.connectSlotsByName(MainWindow)
self.button.clicked.connect(self.onPosButtonClick)
def retranslateUi(self, MainWindow):
_translate = QtCore.QCoreApplication.translate
MainWindow.setWindowTitle(_translate("MainWindow", "Bot"))
self.label_x.setText(_translate("MainWindow", "0"))
self.label_y.setText(_translate("MainWindow", "0"))
self.button.setText(_translate("MainWindow", "Pick Location"))
def on_click(self, x, y, button, pressed):
if pressed:
print('{0} at {1}'.format(
'Pressed' if pressed else 'Released',
(x, y)))
#self.label_x.setText(QtCore.QCoreApplication.translate("MainWindow", str(x)))
#self.label_y.setText(QtCore.QCoreApplication.translate("MainWindow", str(y)))
mouse.Listener.stop()
listener = mouse.Listener(on_click=on_click)
def onPosButtonClick(self):
self.listener.start()
if __name__ == "__main__":
import sys
app = QtWidgets.QApplication(sys.argv)
MainWindow = QtWidgets.QMainWindow()
ui = Ui_MainWindow()
ui.setupUi(MainWindow)
MainWindow.show()
sys.exit(app.exec_())
新 python 顺便说一句
因为你的监听器(on_click
)是一个class成员,你必须在设置回调时提供一个对象。这意味着 listener
不能像现在那样成为 class 变量。相反,您应该在 setupUi
函数中执行此操作:
self.listener = mouse.Listener(on_click=self.on_click)
但是,您根本不需要为此使用 pynput
。 Qt可以做这种鼠标捕获。