细化 X 轴，以便更好地识别距离

Question

我有问题。我有一个数据框 df。我想在 seaborn 的帮助下绘制散点图。但我想改变 x 轴。我希望 x 轴从 4.0 到 5.0 更精细。距离应该更小，例如4.1、4.2 甚至更好。我如何设置才能使 x 轴显示更精细，以便我可以更好地看到 4.0 的值？

我看了seaborn, pylab - changing xticks from float to int , How to change the X axis range in seaborn in python?

d = {'review_scores_accuracy': [1.1, 2.0, 4.5, 5.0, 4.9, 4.8, 4.7], 
     'review_scores_rating': [1.1, 2.0, 4.6, 3.9, 4.2, 4.5, 4.2]}
df = pd.DataFrame(data=d)


fig, ax = plt.subplots(figsize=(20,10))
sns.scatterplot(data=df, x="review_scores_rating", y="review_scores_accuracy", ax = ax ) 
# ax.set_xlim(1,5)
# ax.set_xticks(1,2,3,4,4.1,4.2)
plt.show()

Answer 1

根据

使用matplotlib.ticker

import pandas as pd
import seaborn as sns
import matplotlib.ticker as ticker

d = {'review_scores_accuracy': [1.1, 2.0, 4.5, 5.0, 4.9, 4.8, 4.7], 
 'review_scores_rating': [1.1, 2.0, 4.6, 3.9, 4.2, 4.5, 4.2]}
df = pd.DataFrame(data=d)

fig, ax = plt.subplots(figsize=(20,10))
sns.scatterplot(data=df, x="review_scores_rating",y="review_scores_accuracy", ax=ax) 
ax.xaxis.set_major_locator(ticker.MultipleLocator(0.1))
plt.show()

如果您只想在 4 和 5 之间绘图，请缩小数据范围。

细化 X 轴，以便更好地识别距离

Refine X- Axis so that the distances are better recognizable

python

matplotlib

pandas

seaborn